python np.nan和'=='&'是' [英] python np.nan and '==' & 'is'
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问题描述
当我检查Python操作数的相等性和同一性时，例如 a = [];b = a 我明白了:
When I check for equality and identity of Python operands e.g. a = []; b = a I get this:
a == b => True
a is b => True
我理解.
那么，为什么我要用np.nan获得差异结果?:
so, why I am getting diff result with np.nan?:
a = np.nan; b = a
a == b => False
a is b => True
?
推荐答案
因为 NaN 从不等于任何其他，并且我们使用 == 进行平等比较.
Because NaN is never equal to anything else, and
we use == for performing an equality comparison.
另一方面，用于表示 NaN 的 object 与自身相同，因为 is 用于执行身份比较.
On the other hand the object used to represent NaN is identical to itself, because is is used for doing an identity comparison.
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