改造.如果(！response.isSucessful())获得响应 [英] Retrofit. Get response if (!response.isSucessful())

问题描述

在新的改造中，我进行呼叫并覆盖onResponse和onFailure的2个方法.

In new retrofit I'm making call and overriding 2 methors onResponse and onFailure.

如果改造成功地解析了对我的班级模型的响应，我可以使它变得简单但是，如果(！response.isSucessful())，如何获得服务器响应?

If retrofit sucesfully parsed response to my Class Model I can get it simple but how can I get server response if (!response.isSucessful()) ?

我看到代码错误.原始响应.错误的身体.但是没有看到服务器的响应.这是我的服务器错误...如何从响应中获取它?

I see code error. Raw response. Error body. But didn't see response from server. This is my error from server... how to get it from response?

        {  
 "message": "422 Unprocessable Entity", 
  "errors": {
            "lang": [
              "Lang required."
            ],
            "provider": [
              "Provider required."
            ] 
      },  
         "status_code": 422 }

推荐答案

使用它可以获取错误正文

Using this you can get the error body

  if (response != null && response.errorBody() != null) {
    JSONObject jsonObject = new JSONObject(response.errorBody().string());
    String message = jsonObject.getString("message");
    String errors =  jsonObject.getString("errors");
  }

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