Java的HttpURLConnection类无法连接到ASP.NET API，连接被拒绝 [英] Java HttpURLConnection failed to connect to ASP.NET API, connection refused

问题描述

我尝试使用下面code张贴在Java中的一些数据（在Android Studio中）：

 公共静态字符串downloadContent（URL网址，ContentValues​​ dataToPost）抛出IOException
    InputStream为= NULL;
    INT长度= 500;
    串contentAsString =;    尝试{
        HttpURLConnection的康恩=（HttpURLConnection类）url.openConnection（）;
        conn.setReadTimeout（10000 / *毫秒* /）;
        conn.setConnectTimeout（15000 / *毫秒* /）;
        conn.setRequestMethod（GET）;
        conn.setDoInput（真）;        字符串的queryString = getQuery（dataToPost）;
        conn.connect（）;
        OutputStream的OS = conn.getOutputStream（）;
        INT响应= conn.getResponse code（）;
        但是BufferedWriter作家=新的BufferedWriter（
                新OutputStreamWriter（OS，UTF-8））;
        writer.write（的queryString）;
        writer.flush（）;
        writer.close（）;
        是= conn.getInputStream（）;
        contentAsString = convertInputStreamToString（是，长度）;
    }赶上（MalformedURLException的E）{
        e.printStackTrace（）;
    }赶上（UnsupportedEncodingException五）{
        e.printStackTrace（）;
    }赶上（的ProtocolException E）{
        e.printStackTrace（）;
        e.printStackTrace（）;
    }赶上（IOException异常五）{
        串K = e.getMessage（）;
    } {最后
        如果（是！= NULL）{
            is.close（）;
        }
    }
    返回contentAsString;
}私人静态字符串getQuery（ContentValues​​ PARAMS）抛出UnsupportedEncodingException {
    StringBuilder的结果=新的StringBuilder（）;
    布尔第一= TRUE;    对于（字符串键：params.keySet（））{
        如果（第一）
            第一= FALSE;
        其他
            result.append（与＆amp;）;        result.append（URLEn coder.en code（键，UTF-8））;
        result.append（=）;
        result.append（URLEn coder.en code（params.get（密钥）的ToString（），UTF-8））;
    }    返回result.toString（）;
}公共静态字符串convertInputStreamToString（InputStream的流，INT长度）抛出IOException异常，UnsupportedEncodingException {
    读卡器读卡器= NULL;
    读者=新InputStreamReader的（流，UTF-8）;
    的char []缓冲区=新的char [长度]
    reader.read（缓冲液）;
    返回新的String（缓冲）;
}
 

和我使用下面code调用downloadContent方式：

（？HTTP：//本地主机：59524 / API /测试/ AAA ID = 1）

  URL U =新的URL;
                ContentValues​​ C =新ContentValues​​（）;
                c.put（ID，1）;
                NetworkCommunication.downloadContent（U，C）;
 

我也试过网址更改为的http：//本地主机：59524 / API /测试/ AAA

和我使用C＃（在Visual Studio）所规定的试验一个asp.net MVC API，以及这里的code的API：

 公共类的TestController：ApiController
{
    的[AcceptVerbs（GET，POST）]
    公共IHttpActionResult AAA（INT ID）
    {
        返回OK（好极了！）;
    }
}
 

我能够通过浏览器访问API：

但是为什么在Android Studio中，该程序无法连接？

  

java.net.ConnectException：无法连接到本地主机/ 127.0.0.1
  （端口59524）15000ms后：ECONNREFUSED（连接被拒绝）

在上面抛出IOException异常conn.connect（）;

预期结果：

  

在我发布ID为的http：//本地主机：59524 / API /测试/ AAA ，我
  应该接受一个字符串好极了！

解决方案

使用SOAP Web服务调用asp.net web服务。

我WebSrevice.java类code

 进口org.ksoap2.SoapEnvelope;
进口org.ksoap2.serialization.PropertyInfo;
进口org.ksoap2.serialization.SoapObject;
进口org.ksoap2.serialization.SoapPrimitive;
进口org.ksoap2.serialization.SoapSerializationEnvelope;
进口org.ksoap2.transport.HttpTransportSE;
进口android.R.array;
进口android.util.Log;公共类的WebService {
// web服务的命名空间 - 在WSDL中找到
私人静态字符串NAMESPACE =htt​​p://tempuri.org/;
// URL的Webservice  -  WSDL文件位置
私有静态字符串URL =web服务路径;
//首先确认你更改IP地址
// SOAP动作URI再次命名空间+ Web方法名称
私人静态字符串SOAP_ACTION =htt​​p://tempuri.org/;公共静态字符串invokeCategory（字符串webMethName，字符串compId）{
    串loginStatus =;
    //创建请求
    SoapObject要求=新SoapObject空间（namespace，webMethName）;
    //物业持有输入参数    的PropertyInfo compidPI =新的PropertyInfo（）;
    //设置用户名
    compidPI.setName（companyid）;
    //设置值
    compidPI.setValue（compId）;
    //设置的dataType
    compidPI.setType（为String.class）;
    //添加到Request对象的属性
    request.addProperty（compidPI）;    SoapSerializationEnvelope信封=新SoapSerializationEnvelope（
            SoapEnvelope.VER11）;
    envelope.dotNet = TRUE;
    //设置输出SOAP对象
    envelope.setOutputSoapObject（请求）;
    //创建HTTP调用对象
    HttpTransportSE androidHttpTransport =新HttpTransportSE（URL）;    尝试{
        //调用Web服务
        androidHttpTransport.call（SOAP_ACTION + webMethName，信封）;
        //获取响应
        SoapPrimitive响应=（SoapPrimitive）envelope.getResponse（）;
        //指定为布尔变量变量
        loginStatus = response.toString（）;    }赶上（例外五）{
        //分配错误状态在静态变量真正的错误的
        Login.errored = TRUE;
        e.printStackTrace（）;
    }
    //返回booleam调用对象
    返回loginStatus;
}
}
 

我asynchtask类

 私有类GetCategoryAndProduct扩展的AsyncTask＆LT;弦乐，太虚，太虚＆GT;
{
    @覆盖
    保护无效doInBackground（字符串... PARAMS）{
        //调用Web方法
        数据=（WebService.invokeCategory（的getCategory，COMPANY_ID，0））;
        返回null;
    }    @覆盖
    //一旦WebService的返回响应
    保护无效onPostExecute（虚空结果）{
        //获取服务器响应这里        }
        }
    }
    @覆盖
    在preExecute保护无效（）{    }}
 

我的Asp.net web服务code

  [WebService的空间（namespace =htt​​p://tempuri.org/）]
[WebServiceBinding（ConformsTo = WsiProfiles.BasicProfile1_1）公共类Login_Service：System.Web.Services.WebService
{
     [的WebMethod]
     公共字符串的getCategory（字符串companyid）
     {
        //编写Web服务code在这里     }
 }
 

随意在这里评论

I am trying to use below code to post some data in Java (In Android Studio):

public static String downloadContent(URL url, ContentValues dataToPost) throws IOException {
    InputStream is = null;
    int length = 500;
    String contentAsString = "";

    try {
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setReadTimeout(10000 /* milliseconds */);
        conn.setConnectTimeout(15000 /* milliseconds */);
        conn.setRequestMethod("GET");
        conn.setDoInput(true);

        String queryString = getQuery(dataToPost);
        conn.connect();
        OutputStream os = conn.getOutputStream();
        int response = conn.getResponseCode();
        BufferedWriter writer = new BufferedWriter(
                new OutputStreamWriter(os, "UTF-8"));
        writer.write(queryString);
        writer.flush();
        writer.close();
        is = conn.getInputStream();
        contentAsString = convertInputStreamToString(is, length);
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ProtocolException e) {
        e.printStackTrace();
        e.printStackTrace();
    } catch (IOException e) {
        String k = e.getMessage();
    } finally {
        if (is != null) {
            is.close();
        }
    }
    return contentAsString;
}

private static String getQuery(ContentValues params) throws UnsupportedEncodingException {
    StringBuilder result = new StringBuilder();
    boolean first = true;

    for (String key : params.keySet()) {
        if (first)
            first = false;
        else
            result.append("&");

        result.append(URLEncoder.encode(key, "UTF-8"));
        result.append("=");
        result.append(URLEncoder.encode(params.get(key).toString(), "UTF-8"));
    }

    return result.toString();
}

public static String convertInputStreamToString(InputStream stream, int length) throws IOException, UnsupportedEncodingException {
    Reader reader = null;
    reader = new InputStreamReader(stream, "UTF-8");
    char[] buffer = new char[length];
    reader.read(buffer);
    return new String(buffer);
}

And I'm calling the downloadContent method using below code:

URL u = new URL("http://localhost:59524/api/Test/AAA?id=1");
                ContentValues c = new ContentValues();
                c.put("id", "1");
                NetworkCommunication.downloadContent(u, c);

I've also tried changing the URL to http://localhost:59524/api/Test/AAA

And I made an asp.net MVC API using C# (In visual studio) for testing, and here's the code for the API:

public class TestController : ApiController
{
    [AcceptVerbs("GET", "POST")]
    public IHttpActionResult AAA(int id)
    {
        return Ok("Very good!");
    }
}

I am able to access the API through the browser:

But why in android studio, the program failed to connect?

java.net.ConnectException: failed to connection to localhost/127.0.0.1 (port 59524) after 15000ms: ECONNREFUSED (Connection refused)

The above IOException throws in conn.connect();

Expected result:

When I post the "ID" to http://localhost:59524/api/Test/AAA, I should receive a string "Very good!"

解决方案

use Soap webservice to call the asp.net web service.

My WebSrevice.java class code

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.R.array;
import android.util.Log;

public class WebService {
//Namespace of the Webservice - can be found in WSDL
private static String NAMESPACE = "http://tempuri.org/";
//Webservice URL - WSDL File location   
private static String URL = "webservice path";
//Make sure you changed IP address
//SOAP Action URI again Namespace + Web method name
private static String SOAP_ACTION = "http://tempuri.org/";

public static String invokeCategory( String webMethName, String compId) {
    String loginStatus = "";
    // Create request
    SoapObject request = new SoapObject(NAMESPACE, webMethName);
    // Property which holds input parameters

    PropertyInfo compidPI = new PropertyInfo();
    // Set Username
    compidPI.setName("companyid");
    // Set Value
    compidPI.setValue(compId);
    // Set dataType
    compidPI.setType(String.class);
    // Add the property to request object
    request.addProperty(compidPI);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
            SoapEnvelope.VER11);
    envelope.dotNet = true;
    // Set output SOAP object
    envelope.setOutputSoapObject(request);
    // Create HTTP call object
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

    try {
        // Invoke web service
        androidHttpTransport.call(SOAP_ACTION+webMethName, envelope);
        // Get the response
        SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
        // Assign it to  boolean variable variable
        loginStatus = response.toString();

    } catch (Exception e) {
        //Assign Error Status true in static variable 'errored'
        Login.errored = true;
        e.printStackTrace();
    } 
    //Return booleam to calling object
    return loginStatus;
} 
}

My asynchtask class

private class GetCategoryAndProduct extends AsyncTask<String,Void,Void>  
{
    @Override
    protected Void doInBackground(String... params) {
        //Call Web Method
        data =(WebService.invokeCategory("getCategory",company_id,"0"));
        return null;
    }

    @Override
    //Once WebService returns response
    protected void onPostExecute(Void result) {
        //get server response here

        }
        }
    }
    @Override
    protected void onPreExecute() {

    }

}

My Asp.net webservice code

[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]

public class Login_Service : System.Web.Services.WebService
{   
     [WebMethod]
     public string getCategory(string companyid)
     {
        //write your web service code here

     }
 }

feel free to comment here

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