在SAS中使用正则表达式提取子字符串 [英] extracting substring using regex in sas

问题描述

我有一个像这样的字符串:

I have a string like this:

dfjkldjfdsldfkdslfkd dfkdjd/FR018/HAHDFKDLFDAFHDKFJL/ABCD//NAME/I WANT TO EXTRACT THIS/JJJJ//NAME/blah blah blah

在此字符串中，我希望能够提取字符串 I WANT TO EXTRACT THIS .换句话说，我想提取/ABCD//NAME/之后和/JJJJ 之前的所有内容.

in this string, I want to be able to pull the string I WANT TO EXTRACT THIS. In other words, I want to extract everything that follows /ABCD//NAME/ and before /JJJJ.

如何使用正则表达式编写此代码?

how can I write this using regular expressions?

谢谢

推荐答案

我对SAS不熟悉，但是从

I am not familiar with SAS, but from the documentation it seems like you can do:

re = prxparse('/\/ABCD\/\/NAME\/(.*?)\/(.*?)\/JJJJ/s');
if prxmatch(re, str) then 
    do;
        res = prxposn(re, 1, str);
    end;

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