解构C#元组 [英] Deconstruct a C# Tuple
问题描述
是否可以像F#一样在C#中解构元组?例如,在F#中,我可以这样做:
Is it possible to deconstruct a tuple in C#, similar to F#? For example, in F#, I can do this:
// in F#
let tupleExample = (1234,"ASDF")
let (x,y) = tupleExample
// x has type int
// y has type string
是否可以在C#中做类似的事情?例如
Is it possible to do something similar in C#? e.g.
// in C#
var tupleExample = Tuple.Create(1234,"ASDF");
var (x,y) = tupleExample;
// Compile Error. Maybe I can do this if I use an external library, e.g. LINQ???
还是我必须手动使用Item1,Item2?例如
Or do I have to manually use Item1, Item2? e.g.
// in C#
var tupleExample = Tuple.Create(1234,"ASDF");
var x = tupleExample.Item1;
var y = tupleExample.Item2;
推荐答案
You can use Deconstruction but you should use C#7 for this purpose:
消费元组的另一种方法是解构它们.解构声明是用于将元组(或其他值)拆分为并将其分别分配给新变量
Another way to consume tuples is to deconstruct them. A deconstructing declaration is a syntax for splitting a tuple (or other value) into its parts and assigning those parts individually to fresh variables
因此,以下内容在C#7中有效:
So the following is valid in C#7:
var tupleExample = Tuple.Create(1234, "ASDF");
//Or even simpler in C#7
var tupleExample = (1234, "ASDF");//Represents a value tuple
var (x, y) = tupleExample;
Deconstruct
方法也可以是扩展方法,如果您想解构不属于您的类型,该方法将非常有用.例如,可以使用如下扩展方法对旧的 System.Tuple
类进行解构:(
The Deconstruct
method can also be an extension method, which can be useful if you want to deconstruct a type that you don’t own. The old System.Tuple
classes, for example, can be deconstructed using extension methods like this one: (Tuple deconstruction in C# 7):
public static void Deconstruct<T1, T2>(this Tuple<T1, T2> tuple, out T1 item1, out T2 item2)
{
item1 = tuple.Item1;
item2 = tuple.Item2;
}
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