Python open()提供FileNotFoundError/IOError:Errno 2没有这样的文件或目录 [英] Python open() gives FileNotFoundError/IOError: Errno 2 No such file or directory

问题描述

由于某种原因，我的代码无法打开简单文件:

For some reason my code is having trouble opening a simple file:

这是代码:

file1 = open('recentlyUpdated.yaml')

错误是:

IOError: [Errno 2] No such file or directory: 'recentlyUpdated.yaml'

• 自然地，我检查了文件名是否正确.
• 我尝试过移动文件，为 open()提供文件的完整路径，但似乎没有任何作用.
• Naturally I checked that this is the correct name of the file.
• I have tried moving around the file, giving open() the full path to the file and none of it seems to work.

推荐答案

• 确保文件存在:使用 os.listdir()查看当前工作目录中的文件列表
• 使用 os.getcwd()确保您位于自己认为的目录中(如果从IDE启动代码，则很可能位于其他目录中)
• 然后您可以:
  • 调用 os.chdir(dir)，其中 dir 是文件所在的文件夹找到文件，然后像以前一样使用文件名打开文件.
  • 在您的 open 调用中指定文件的绝对路径.
  • Make sure the file exists: use os.listdir() to see the list of files in the current working directory
  • Make sure you're in the directory you think you're in with os.getcwd() (if you launch your code from an IDE, you may well be in a different directory)
  • You can then either:
    • Call os.chdir(dir), dir being the folder where the file is located, then open the file with just its name like you were doing.
    • Specify an absolute path to the file in your open call.
    • 如果您不使用原始字符串，则必须转义每个反斜杠:'C:\\ User \\ Bob \\ ...'
    • 正斜杠在Windows 'C:/Python32'上也可以使用，不需要转义.
    • If you don't use raw-string, you have to escape every backslash: 'C:\\User\\Bob\\...'
    • Forward-slashes also work on Windows 'C:/Python32' and do not need to be escaped.

    让我澄清一下Python如何查找文件:

    Let me clarify how Python finds files:

    • 绝对路径是从计算机的根目录开始的路径，例如，如果您使用的是Windows，则为"C:\ Python \ scripts ..".
    • 相对路径是不以您计算机的根目录开头的路径，而是相对于称为工作目录的东西的路径.您可以通过调用 os.getcwd()来查看Python的当前工作目录.
    • An absolute path is a path that starts with your computer's root directory, for example 'C:\Python\scripts..' if you're on Windows.
    • A relative path is a path that does not start with your computer's root directory, and is instead relative to something called the working directory. You can view Python's current working directory by calling os.getcwd().

    如果您尝试执行 open('sortedLists.yaml')，Python将看到您正在向其传递相对路径，因此它将在当前工作目录中搜索文件.调用 os.chdir 将更改当前工作目录.

    If you try to do open('sortedLists.yaml'), Python will see that you are passing it a relative path, so it will search for the file inside the current working directory. Calling os.chdir will change the current working directory.

    示例:假设在 C:\ Folder 中找到了 file.txt .

    Example: Let's say file.txt is found in C:\Folder.

    要打开它，您可以执行以下操作:

    To open it, you can do:

    os.chdir(r'C:\Folder')
    open('file.txt') #relative path, looks inside the current working directory
    

    或

    open(r'C:\Folder\file.txt') #full path
    

    这篇关于Python open()提供FileNotFoundError/IOError:Errno 2没有这样的文件或目录的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！