使用PHP递归获取最新文件 [英] Get most recent files recursively with PHP
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问题描述
我正在寻找递归列出目录中五个最新文件的代码.
I am looking for code which lists the five most recent files in a directory recursively.
这是非递归代码,如果它是递归的,对我来说将是完美的:
This is non-recursive code, and would be perfect for me if it was recursive:
<?php
$show = 0; // Leave as 0 for all
$dir = 'sat/'; // Leave as blank for current
if($dir) chdir($dir);
$files = glob( '*.{html,php,php4,txt}', GLOB_BRACE );
usort( $files, 'filemtime_compare' );
function filemtime_compare( $a, $b )
{
return filemtime( $b ) - filemtime( $a );
}
$i = 0;
foreach ( $files as $file )
{
++$i;
if ( $i == $show ) break;
echo $file . ' - ' . date( 'D, d M y H:i:s', filemtime($file) ) . '<br />' . "\n"; /* This is the output line */
}
?>
是否可以修改它以递归方式扫描目录?
It is possible to modify it to scan directories recursively?
推荐答案
这是我的第一个版本(经过测试,可以正常运行):
This was my first version (tested, working):
function latest($searchDir, array $files = array()) {
$search = opendir($searchDir);
$dirs = array();
while($item = readdir($search)) {
if ($item == '.' || $item == '..') { continue; }
if (is_dir($searchDir.'/'.$item)) {
$dirs[] = $searchDir.'/'.$item;
}
if (is_file($searchDir.'/'.$item)) {
$ftime = filemtime($searchDir.'/'.$item);
$files[$ftime] = $searchDir.'/'.$item;
}
}
closedir($search);
if (count($dirs) > 0) {
foreach ($dirs as $dir) {
$files += latest($dir,$files);
}
}
krsort($files);
$files = array_slice($files, 0, 5, true);
return $files;
}
但是我喜欢byte对 glob()
的使用,所以这是他的略微修改版本,可以返回相同的格式:
But I like byte's usage of glob()
, so here is a slightly modified version of his to return the same format:
function top5modsEx($dir) {
$mods = array();
foreach (glob($dir . '/*') as $f) {
$mods[filemtime($f)] = $f;
}
krsort($mods);
return array_slice($mods, 0, 5, true);
}
这将返回文件被修改为数组元素的键的时间(UNIX时间戳格式).
This returns the time (UNIX Timestamp format) that the file was modified as the key of the element in the array.
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