使用Java打开文件的属性窗口 [英] Open a file's properties window using Java

问题描述

这只是Windows中有关Java的问题.

This is a question only regarding Java in Windows.

我需要一个可以调用此窗口的方法:

I need a method that will call this window:

因此，基本上该方法应类似于:

So essentially the method should be something like:

public void openProperties(File file){ // or String fileName

}

因此，语句: opernProperties(new File(test.txt)); 应该打开上面的窗口.

So the statement: opernProperties(new File(test.txt)); should open the above window.

因此，为了澄清起见，我不想阅读和管理属性.我只想打开属性窗口.

So just to clarify, I do not want to read and manage the properties. I just want to open the properties window.

推荐答案

我能够使用以下命令显示文件属性窗口:

I was able to display the file properties window using the following:

• 转到 https://oss.sonatype.org/content/repositories/snapshots/net/java/dev/jna/
• 下载快照JAR jna-4.3.0-20160510.203907-1.jar和jna-platform-4.3.0-20160510.204004-1.jar(由于它是4.2，因此我们无法使用maven仓库中的最新版本).2并且没有SHELLEXECUTEINFO)
• 加载罐子并在下面粘贴以下代码

这将显示属性窗口，并延迟3秒.请注意，如果您不希望窗口在3秒后自动关闭，则alk讨论过将窗口传递给hwnd成员

This should display the properties window with a delay of 3 seconds. Notice that alk talked about passing the window through hwnd member if you don't want it to auto close after the 3 seconds

public static void main(String[] args) throws InterruptedException {
        ShellAPI.SHELLEXECUTEINFO shellExecuteInfo = new ShellAPI.SHELLEXECUTEINFO();
        shellExecuteInfo.lpFile = "C:\\setup.log";
        shellExecuteInfo.nShow = User32.SW_SHOW;
        shellExecuteInfo.fMask = 0x0000000C;
        shellExecuteInfo.lpVerb = "properties";
        if (Shell32.INSTANCE.ShellExecuteEx(shellExecuteInfo)){
            Thread.sleep(3000);
        }
    }

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