"ValueError:对关闭文件的I/O操作"在循环写入文件时 [英] "ValueError: I/O operation on closed file" while writing to a file in a loop

问题描述

我必须将file.txt分成更多文件.这是代码:

I have to divide a file.txt into more files. Here's the code:

a = 0
b = open("sorgente.txt", "r")
c = 5
d = 16 // c
e = 1
f = open("out"+str(e)+".txt", "w")
for line in b:
    a += 1
    f.writelines(line)
    if a == d:
        e += 1
        a = 0
        f.close()
f.close()

所以，如果我运行它，它将给我这个错误:

So , if i run it it gives me this error :

todoController\WordlistSplitter.py", line 9, in <module>
    f.writelines(line)
ValueError: I/O operation on closed file

我了解到，如果执行for循环，文件将关闭，因此我尝试将f放入for循环中，但由于没有得到，所以它不起作用:

I understood that if you do a for loop the file gets closed so I tried to put the f in the for loop but it doesn't work because instead of getting:

out1.txt
 1
 2
 3
 4

out2.txt
 5
 6
 7
 8

我只得到文件的最后一行.我应该怎么办?有什么方法可以让我回忆起之前定义的打开函数?

I get only the last line of the file. What should I do? Are there any way I can recall the open function I defined earlier?

推荐答案

您在 for 循环内 f.close()，然后不要 open 作为 f 的新文件，因此在下一次迭代时出错.您还应该使用 with 来处理文件，这样就无需显式地 close 来处理文件.

You f.close() inside the for loop, then do not open a new file as f, hence the error on the next iteration. You should also use with to handle files, which saves you needing to explicitly close them.

由于您希望一次向每个 out 文件写入四行，因此可以执行以下操作:

As you want to write four lines at a time to each out file, you can do this as follows:

file_num = 0
with open("sorgente.txt") as in_file:
    for line_num, line in enumerate(in_file):
        if not line_num % 4:
            file_num += 1
        with open("out{0}.txt".format(file_num), "a") as out_file:
            out_file.writelines(line)

请注意，我已经使用变量名使事情更清楚了.

Note that I have used variable names to make it a bit clearer what is happening.

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