查找文件，然后CD到Linux中的该目录 [英] Find file then cd to that directory in Linux

问题描述

在shell脚本中，我如何查找具有特定名称的文件，然后导航到该目录以对该文件进行进一步的操作?

In a shell script how would I find a file by a particular name and then navigate to that directory to do further operations on it?

从这里，我将文件复制到另一个目录(但是我已经可以将其添加到上下文中了.)

From here I am going to copy the file across to another directory (but I can do that already just adding it in for context.)

推荐答案

您可以使用类似以下内容的

You can use something like:

pax[/home/pax]> cd "$(dirname "$(find / -type f -name ls | head -1)")"
pax[/usr/bin]> _

这将找到第一个 ls 常规文件，然后转到该目录.

This will locate the first ls regular file then change to that directory.

就每个位的作用而言:

• 查找将从/开始并向下搜索，列出所有称为 ls (-name ls ).您还可以添加其他内容到 find 中，以进一步限制您获取的文件.
• 通过 head -1 的管道将过滤掉除第一个管道以外的所有管道.
• $()是一种获取命令输出并将其放置在命令行中的另一个命令的方法.
• dirname 可以获取完整的文件规范并为您提供路径位.
• cd 只是更改到该目录.

• The find will start at / and search down, listing out all regular files (-type f) called ls (-name ls). There are other things you can add to find to further restrict the files you get.
• The piping through head -1 will filter out all but the first.
• $() is a way to take the output of a command and put it on the command line for another command.
• dirname can take a full file specification and give you the path bit.
• cd just changes to that directory.

如果按顺序执行每个位，则可以看到发生的情况:

If you execute each bit in sequence, you can see what happens:

pax[/home/pax]> find / -type f -name ls
/usr/bin/ls

pax[/home/pax]> find / -type f -name ls | head -1
/usr/bin/ls

pax[/home/pax]> dirname "$(find / -type f -name ls | head -1)"
/usr/bin

pax[/home/pax]> cd "$(dirname "$(find / -type f -name ls | head -1)")"

pax[/usr/bin]> _

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