如何检测URL中是否含有成人或非法内容？ [英] How to detect whether URL contains adult or illegal content?

问题描述

有没有在那里，检查成人或非法内容的API？

Is there any API out there that checks for adult or illegal content?

我目前使用谷歌的安全浏览API来检查恶意软件和放大器;网络钓鱼。

I'm currently using google's browse safe api to check for malware & phishing.

不过，我想检查是否是成年人。类似谷歌的安全搜索。

However, I would like to check whether it is adult. Similar to Google's SafeSearch.

任何想法？

推荐答案

有一些公司在那里，提供自动链接分类服务，但几乎所有的人都需要钱。

There are a number of companies out there that provide automatic url classification services, however nearly all of them cost money.

我已经有点与 Zvelo 互动，它似乎是相当不错，并有一个大型数据库分类的URL。再次。其付费服务队，所以我不知道是否符合您的条件。

I've had a bit of interaction with Zvelo which it seems to be quite good and has a large database of classified urls. Again. its a paid sevice, so I'm not sure if that meets your criteria.

从快速谷歌搜索我也发现;

From a quick google search I also found;

• Clearswift公司 - 付费


• Alhem分布式网址分类工具 - 免费


• Websense的 - 付费

• ClearSwift - Paid
• Alhem Distributed Url Classification Tool - Free
• WebSense - Paid

只要记住，没有系统将是100％，你会得到一些误报和漏报。

Just bear in mind that no system is going to be 100% and that you'll get some false positives and negatives.

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