在一行/函数中将中间件添加到所有firebase函数 [英] Add middleware to all firebase functions in one line / function

问题描述

在 express 中，您可以添加诸如 app.use(cors())之类的中间件，该中间件会将其添加到所有端点，但是我找不到类似的东西在Firebase示例中.这是示例(请参见下文)将其应用到所有功能中.但是，由于我有很多功能，因此我想全局地 应用中间件(cors或其他).

In express you can add middleware such as app.use(cors()) which adds it to all of the endpoints, however I can't find something similar in firebase examples. Here is the example (see below) of how to apply it in every function. However I want to apply the middleware (cors or other) globally, as I have many functions.

import * as cors from 'cors';
const corsHandler = cors({origin: true});

export const exampleFunction= functions.https.onRequest(async (request, response) => {
       corsHandler(request, response, () => { return handler(req, res) });
});

firebase中的 app.use()等效项是什么?是添加并表达服务器 仅选项?

What is the equivalent of app.use() in firebase? Is adding and express server the only option?

推荐答案

使用currying 创建处理程序，您必须在所有函数中重复该处理程序，但是比每次编写中间件都要容易:

Use currying to create a handler, you have to repeat it across all the functions, but it's easier than writing the middleware each time:

const applyMiddleware = handler => (req, res) => {
  return cors(req, res, () => {
    return handler(req, res)
  })
}
exports.handler = functions.https.onRequest(applyMiddleware(handler))

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