在Firebase Swift中删除特定的子节点 [英] Delete a specific child node in Firebase swift
问题描述
您能帮我解决这个问题吗?我想删除数据库中的特定消息.
Can you help me solve this problem? I want to delete a specific message in the database.
我的数据库如下:
• MESSAGES
••(childByAutoID XXXXXXXXX)
•••email: user1@gmail.com
•••message: hello there
•••timestamp: 329842938592
•
••(childByAutoID XXXXXXXXX)
•••email: user1@gmail.com
•••message: where are you?
•••timestamp: 872985042750
•
••(childByAutoID XXXXXXXXX)
•••email: user2@gmail.com
•••message: basketball?
•••timestamp: 845938459349
我尝试使用此代码,但它从当前用户(user1)删除了错误的帖子.
I tried using this code but it deletes the wrong post from the current user (user1).
func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCellEditingStyle, forRowAt indexPath: IndexPath) {
if (editingStyle == .delete) {
jobRequests.remove(at: indexPath.row)
tableView.deleteRows(at: [indexPath], with: .automatic)
if let email = Auth.auth().currentUser?.email {
Database.database().reference().child("MESSAGES").queryOrdered(byChild: "email").queryEqual(toValue: email).observeSingleEvent(of: .childAdded, with: { (snapshot) in
snapshot.ref.removeValue()
那么我该如何删除消息你在哪里?"及其成员.
so how can i delete the message "where are you?" and its members.
推荐答案
查询需要与您要删除的内容匹配.
The query needs to match what you want to delete.
如果要删除文本为您在哪里?"
的消息,则应查询以下内容:
If you want to delete the message with text "where are you?"
, you should query for that:
let messagesRef = Database.database().reference().child("MESSAGES")
messagesRef.queryOrdered(byChild: "message").queryEqual(toValue: "where are you?")...
如果要删除带有特定电子邮件的所有邮件,则应查询该邮件:
If you want to delete all messages with a specific email, you should query for that:
messagesRef.queryOrdered(byChild: "email").queryEqual(toValue: "email1@gmail.com")...
如果要删除特定消息,则必须知道其密钥,然后:
If you want to delete a specific message, you must know its key and then:
messagesRef.queryOrderedByKey().queryEqual(toValue: "-L....")...
或更惯用的:
messagesRef.child("-L....").observeSingleEvent(of: .value, with: { (snapshot) in
snapshot.ref.removeValue()
(请注意,由于我们不再使用查询,因此此处观察的是 value
的值,而不是 .childAdded
.
(Note that we're observing value
here, not .childAdded
, since we're no long using a query.
或更简单;由于您已经知道要删除的节点的完整路径,因此您无需读取任何内容:
Or even simpler; since you already know the full path of the node to delete, you don't need to read anything:
messagesRef.child("-L....").removeValue()
这篇关于在Firebase Swift中删除特定的子节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!