将查询参数传递给Flask装饰器 [英] Pass query parameters to Flask decorator

问题描述

我正在为我的Flask服务器设置一个令牌身份验证系统，并且我希望能够设置一个装饰器，使其看起来像这样:

I'm setting up a token auth system for my Flask server, and I want to be able to setup a decorator to look something like this:

@app.route('/my/data/')
@requires_token_auth
def get_my_endpoint_data():
    """Return JSON data""""
    return get_data()

然后，我将按/my/data?token = myawesometokenvalue这样的终点

Then I'll hit the endpoint like /my/data?token=myawesometokenvalue

我已经将装饰器功能设置为

I've setup my decorator function like

def requires_token_auth(f):
    @wraps(f)
    def wrapped(*args, **kwargs):
        ... do stuff ...
        return f(*args, **kwargs)
return wrapped

不幸的是，'token'参数在args内部不可用.问题似乎是Flask通过了req.view_args，而不是req.args.

Unfortunately, the 'token' parameter is not made available inside of args. The problem seems to be that Flask passes the req.view_args through, instead of req.args.

*来自烧瓶的app.py *

1344         return self.view_functions[rule.endpoint](**req.view_args)

如何从包装函数内部访问查询参数?

How can I access query parameters from inside of a wrapped function?

推荐答案

由于这是烧瓶查询参数修饰器"的第一个google结果，因此这是我最终在路径顶部添加查询参数的解决方案方法中的参数:

Since this is the first google result for "flask query parameters decorator", this is the solution I ended up with to add the query parameters, on top of path parameters in methods:

def query_params(f):
    """
    Decorator that will read the query parameters for the request.
    The names are the names that are mapped in the function.
    """
    parameter_names = inspect.getargspec(f).args

    @wraps(f)
    def logic(*args, **kw):
        params = dict(kw)

        for parameter_name in parameter_names:
            if parameter_name in request.args:
                params[parameter_name] = request.args.get(parameter_name)

        return f(**params)

    return logic

@app.route('/hello/<uid>', methods=['GET', 'POST'])
@query_params
def hello_world(uid, name):
    return jsonify({
        'uid': uid,
        'name': name
    })

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