在烧瓶上获取查询字符串作为函数参数 [英] Get query string as function parameters on flask

问题描述

有没有办法在烧瓶上获取查询字符串作为函数参数?
例如，请求将是这样.

Is there a way to get query string as function parameters on flask?
For example, the request will be like this.

http://localhost:5000/user?age=15&gender=Male

并希望与此类似的代码.

And hope the code similar to this.

@app.route("/user")
def getUser(age, gender):
...

推荐答案

如果您愿意编写装饰器，则一切皆有可能:

If you are willing to write a decorator, anything is possible:

from functools import wraps

def extract_args(*names, **names_and_processors):
    user_args = ([{"key": name} for name in names] +
        [{"key": key, "type": processor}
            for (key, processor) in names_and_processors.items()])

    def decorator(f):
        @wraps(f)
        def wrapper(*args, **kwargs):
            final_args, final_kwargs = args_from_request(user_args, args, kwargs)
            return f(*final_args, **final_kwargs)
        return wrapper
    return decorator if len(names) < 1 or not is_callable(names[0]) else decorator(names[0])

def args_from_request(to_extract, provided_args, provided_kwargs):
    # Ignoring provided_* here - ideally, you'd merge them
    # in whatever way makes the most sense for your application
    results = {}
    for arg in to_extract:
        result[arg["key"]] = request.args.get(**arg)
    return provided_args, results

用法:

@app.route("/somewhere")
@extract_args("gender", age=int)
def somewhere(gender, age):
    return jsonify(gender=gender, age=age)

这篇关于在烧瓶上获取查询字符串作为函数参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！