如何通过给定的分隔符在列表内拆分字符串并展平子字符串列表 [英] How to split strings inside a list by given delimiter and flatten the sub-strings lists

问题描述

我有一个带有此列表的python脚本:

I have a python script with this list:

blocks = [
  "item-1",
  "item-2",
  "item-3.0;item-3.1;item-3.2"
]

我已经尝试过了:

for (i, block) in enumerate(blocks):
  if ";" in block:
    [blocks.insert(i, c) for c in block.split(";")]
  else:
    blocks.insert(i, block)

要获取此信息:

blocks = [
  "item-1",
  "item-2",
  "item-3.0",
  "item-3.1",
  "item-3.2"
]

不幸的是，我的代码不断覆盖列表中的元素，我只剩下这个了:

Unfortunately my code keeps overwriting the the elements in the list, and I'm left with this:

blocks = [
  "item-1",
  "item-2",
  "item-3.2"
]

如何修改脚本以允许在列表内拆分字符串，然后将新的子字符串插入原始字符串的位置，而不会覆盖列表中的其他元素?

How can I modify the script to allow me to split a string inside of a list and then insert the new sub-strings into the position of the original string without overwriting the other elements in the list?

推荐答案

创建新列表可能会更容易:

It would probably be easier to make a new list:

blocks = [
  "item-1",
  "item-2",
  "item-3.0;item-3.1;item-3.2"
]

new_blocks = []

for block in blocks:
    for c in block.split(";"):
        new_blocks.append(c)

 # new_blocks = ['item-1', 'item-2', 'item-3.0', 'item-3.1', 'item-3.2']

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