最多可以容纳多少个浮点类型? [英] what's the largest number float type can hold?
问题描述
我是编程的新手，最近又提出了这个简单的问题.浮点型有32位，其中8位是整数部分(尾数).所以我的问题是浮点型可以容纳大于255.9999的数字吗?
I'm new to programming and have recently come up with this simple question . float type has 32 bits in which 8 bits are for the whole number part (the mantissa). so my question is can float type hold numbers bigger than 255.9999 ?
如果有人告诉我为什么这段代码的行为异常，我也将不胜感激.是相关问题吗?
and I would also appreciate if someone told me why this code is behaving unexpectedly. Is it a related issue?
int main(){
float a=123456789.1;
printf("%lf",a);
return 0;
}
输出为:
123456792.000000
推荐答案
code>< float.h> -浮点类型的数字限制有您的答案，特别是...
<float.h> -- Numeric limits of floating point types has your answers, specifically...
- FLT_MAX
- DBL_MAX
- LDBL_MAX
float ， double 和 long double 的最大极限值
maximum finite value of float, double and long double respectively
...和...
- FLT_DIG
- DBL_DIG
- LDBL_DIG
保证保留在文本中的小数位数-> float / double / long double ->文本往返由于舍入或溢出
number of decimal digits that are guaranteed to be preserved in text -> float/double/long double -> text roundtrip without change due to rounding or overflow
最后一部分的意思是，不再保证 float 的值(即更高的有效数字)比 FLT_DIG 更长的值.
That last part is meant to say that a float value longer (i.e. more significant digits) than FLT_DIG is no longer guaranteed to be precisely representable.
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