尝试在对象中的if else语句中使用for循环 [英] trying to use a for loop with if else statement in objects

问题描述

我正在尝试编写一个函数，该函数将通过一个包含对象的变量进行迭代.如果传入的是对象属性的名字，则应该为true.如果不是，您应该得到错误.但是，无论我通过什么功能，我总会得到错误的结果.任何帮助将不胜感激.

I'm trying to write a function that will iterate through a variable holding objects. If you pass in a first name that is an object property, you should get true. If not, you should get false. However, no matter what I pass through the function, I always get false. Any help is greatly appreciated.

var contacts = [
{
    "firstName": "Akira",
    "lastName": "Laine",
    "number": "0543236543",
    "likes": ["Pizza", "Coding", "Brownie Points"]
},
{
    "firstName": "Harry",
    "lastName": "Potter",
    "number": "0994372684",
    "likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
    "firstName": "Sherlock",
    "lastName": "Holmes",
    "number": "0487345643",
    "likes": ["Intriguing Cases", "Violin"]
},
{
    "firstName": "Kristian",
    "lastName": "Vos",
    "number": "unknown",
    "likes": ["Javascript", "Gaming", "Foxes"]
}
];


function attempt(firstName){
for(var i = 0;i < contacts.length; i++){
    if(contacts[i].firstName==firstName){
    return true;
    } else {
      return false;
    }
 }  
}

推荐答案

仔细思考一下逻辑:在第一个循环中会发生什么?函数对 if / else 的响应是什么?正确的！它会立即返回 true 或 false ，而不会循环浏览其余条目.

Think through the logic for a moment: What happens on the first loop? What does the function do in response to the if/else? Right! It returns true or false right away, without looping through the remaining entries at all.

您需要完全删除 else ，然后将 return false 移到外部循环中:

You need to remove the else entirely and move return false to outside the loop:

function attempt(firstName) {
    for (var i = 0; i < contacts.length; i++) {
        if (contacts[i].firstName == firstName) {
            return true;
        }
    }
    return false;
}

---

旁注: Array#some 正是为此用例而设计的:

---

Side note: Array#some is designed for exactly this use case:

function attempt(firstName) {
    return contacts.some(function(entry) {
        return entry.firstName == firstName;
    });
}

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