Python:同时打印列表中的所有字符串 [英] Python: print all the string from list at the same time

问题描述

例如，我有一个列表 a .当我在for循环中执行此操作时，可以打印其所有元素.但是，当我在for循环之外执行此操作时，它仅显示最后一个.如何在for循环外将它们全部打印出来?预先感谢.

For example, I have a list a. When I do it in a for loop, I can print all of its elements. But when I do it outside of the for loop, it only prints the last one. How can I print them all outside the for loop? Thanks in advance.

代码:

a=['a is apple','b is banana','c is cherry']
for i in a:
    print(i)
print("====================")
print(i)

它打印:

a is apple
b is banana
c is cherry
====================
c is cherry

我想要的结果是:

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

推荐答案

您可以将 print 与 * 和换行符分开使用:

You can use print with * and a separator of a newline:

print(*a, sep='\n')
print("====================")
print(*a, sep='\n')

输出:

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

print(* a)等效于 print(a [0]，a [1]，a [2]，...).这样可以在中间留有空白.使用 sep ='\ n'覆盖此默认设置，则会换行.

The print(*a) is equivalent to print(a[0], a[1], a[2], ...). This would print it with a white space in between. Overriding this default with sep='\n' gives you a newline instead.

如果要重用它，请编写自己的小型辅助函数:

If you want to reuse it, write your own, small helper function:

def myprint(a):
    print(*a, sep='\n')

myprint(a)

单线替代，但可读性较低:

A one-liner alternative, but arguably less readable:

print(*(a + ["=" * 20] + a), sep='\n')

输出:

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

在Python 2中，使用以下命令打开" Python-3样式的打印功能:

In Python 2 "turn on" the Python-3-style print function with:

from __future__ import print_function

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