如何将\ n传播到sympy.latex() [英] How to propagate `\n` to sympy.latex()

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问题描述

目标是将具有6个以上参数的多项式格式化为绘图标题.这是我的字符串表达式函数的多项式参数,灵感来自此答案,然后是 sym.latex():

The Goal is to format a polynomial with more than 6 parameters into a plot title. Here is my polynomial parameter to string expression function, inspired by this answer, followed by sym.latex():

def func(p_list):
    str_expr = ""       
    for i in range(len(p_list)-1,-1,-1):
        if (i%2 == 0 and i !=len(p_list)):
            str_expr =str_expr + " \n "
        if p_list[i]>0:
            sign = " +"
        else:
            sign = ""
        if i > 1:
            str_expr = str_expr+" + %s*x**%s"%(p_list[i],i)
        if i == 1:
            str_expr = str_expr+" + %s*x"%(p_list[i])
        if i == 0:
            str_expr = str_expr+sign+" %s"%(p_list[i])
        print("str_expr",str_expr)
        return sym.sympify(str_expr)
                    
popt = [-2,1,1] # some toy data
tex = sym.latex(func(popt))
print("tex",tex)

输出:

str_expr
  + -1*x**2 + 1*x
  -2
tex - x^{2} + x - 2 

str_expr 中的

可见从 \ n 的换行符,但是在 sympy.latex 输出中,该换行符消失了.

in str_expr the line breaks from \n are visible, yet in the sympy.latex output the are gone.

如何传播此换行符?

我使用@ wsdookadr答案并对其进行了修改,以便plt.title将函数的结果作为文本作为参数

I took @ wsdookadr answer and modified it, so that plt.title takes the result of the function as text the argument


def tex_multiline_poly(e, chunk_size=2, separator="\n"):
    tex = ""
    # split into monomials
    print("reversed(e.args)",reversed(e.args))
   
    mono = list(e.args)
    print("mono",mono)
    mono.reverse()
    print("mono",mono)
    # we're going split the list of monomials into chunks of chunk_size
    # serialize each chunk, and insert separators between the chunks
    for i in range(0,len(mono),chunk_size):
        chunk = mono[i:i + chunk_size]
        print("sum(chunk)",sum(chunk))
        print("sym.latex(sum(chunk))",sym.latex(sum(chunk)))
        if i == 0:
            tex += r'$f(x)= %s$'%(sym.latex(sum(chunk)))+separator
        else:
            tex += '$%s$'%(sym.latex(sum(chunk))) + separator
    return tex

popt = est.params
x = sym.symbols('x')
p = sym.Poly.from_list(reversed(popt),gens=x)
tex = tex_multiline_poly(p.as_expr(),chunk_size=2)
plt.title(text=tex)

推荐答案

在您的代码中,您将为除最后一个之外的所有偶数幂单项式插入换行符.

In your code, you're inserting a linebreak for every even-power monomial, except for the last one.

   if (i%2 == 0 and i !=len(p_list)):
       str_expr =str_expr + " \n "

由于您只是从系数列表中构建多项式,因此可以简化代码.

Since you are just building a polynomial from a list of coefficients, your code can be simplified.

通常,我们想要的是象征性地构建/转换/处理事物,最后只对它们进行序列化并以某种特定格式打印结果

Generally what we want is to build/transform/handle things symbolically, and only at the end serialize them and print the result in some specific format

import sympy as sym

x = sym.symbols('x')

def func(p_list):
    expr = 0
    for i in range(len(p_list)-1,-1,-1):
        expr += p_list[i] * (x ** i)
    return sym.sympify(expr)

popt = [-2,1,1]
p = func(popt)
p_tex = sym.latex(p)
p_str = str(p)
print("str:", p_str)
print("tex:", p_tex)

输出:

str: x**2 + x - 2
tex: x^{2} + x - 2

我们可以通过使用SymPy的内置函数从系数列表中构建 poly来进一步简化此操作:

We could simplify this even further by using SymPy's built-in functions to build the poly from a list of coefficients:

import sympy as sym
from sympy import symbols

popt = [-2,1,1]

x = symbols('x')
p = sym.Poly.from_list(reversed(popt),gens=x)
p_tex = sym.latex(p.as_expr())
p_str = str(p.as_expr())
print("str:", p_str)
print("tex:", p_tex)

输出:

str: x**2 + x - 2
tex: x^{2} + x - 2

输出看起来是否像您期望的那样?

Does the output look like what you would expect?

更新:

在详细了解了用例之后,这是一个版本,该版本以表达式的乳胶形式在每N = 2个单项式中插入分隔符.

After learning more about the use-case, here's a version that inserts separators every N=2 monomials in the latex form of your expression.

import sympy as sym
from sympy import symbols

popt = [-2,1,1]

x = symbols('x')
p = sym.Poly.from_list(reversed(popt),gens=x)

def tex_multiline_poly(e, chunk_size=2, separator="\n"):
    tex = ""
    # split into monomials
    mono = list(reversed(e.args))
    # we're going split the list of monomials into chunks of chunk_size
    # serialize each chunk, and insert separators between the chunks
    for i in range(0,len(mono),chunk_size):
        chunk = mono[i:i + chunk_size]
        tex += sym.latex(sum(chunk)) + separator
    return tex

p_tex = tex_multiline_poly(p.as_expr(),chunk_size=2)
p_str = str(p.as_expr())

print("str:",p_str)
print("tex:",p_tex)

输出:

str: x**2 + x - 2
tex: x^{2} + x
-2

错误的编辑

这篇关于如何将\ n传播到sympy.latex()的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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