让递归函数永远运行? [英] Leaving recursive functions running forever?

问题描述

我碰到一个函数，里面有一个 setTimeout ，超时时间呈指数增长(timeout * = 2).

I came across a function where it had a setTimeout inside with a timeout growing exponentially (timeout *= 2).

let timeout = 10000
function foo() {
    // doSomething without breaking, returning
    setTimeout(foo, timeout)
    timeout *= 2;
}
foo()

这似乎不应该是一个问题，并且直观地感觉到 setInterval 有点已经在做(具有无限循环，直到有可能被取消为止)，我的问题在于方法本身.

It seems that this should not be a problem and intuitively feels like setInterval is kinda doing the same already (having an infinite loop until it's cancelled if ever), however, my question is in the approach itself.

• 这是否可能导致内存泄漏?
• 仍然限制该函数的调用次数更好/更清晰吗?
• 其他语言会使用这种方法吗?或者在JS世界之外还有其他不同的心态?

推荐答案

这不是递归函数调用.调用 setTimeout 会导致 foo 在以后的JavaScript事件循环中被调用.

This is not a recursive function call. The call to setTimeout will cause foo to be called by the JavaScript event loop at a later time.

此代码不会导致堆栈溢出或任何此类问题.它应该是完全安全的.

This code will not cause a stack overflow or any such problems. It should be completely safe.

要深入了解其工作原理，建议阅读JS事件循环和微任务.

To understand how this works in-depth, I suggest reading up on the JS event loop and microtasks.

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