Python打印功能输出多次 [英] Python printing function output multiple times

问题描述

我正在编写一个程序来完成某些python挑战.我创建了该程序，它基本上完成了我需要做的所有事情，除了它有一个怪异的怪癖.它会多次打印我想要的输出.

I'm making a program to accomplish a certain python challenge. I created the program, and it basically does everything I need it to do, except it's got one weird quirk; it prints the output I want multiple times.

cmdname = input("Enter the name of your command.\n>")
print("Enter options one by one. If the option has an argument, put a * at the end of the option. When done entering options, enter \"q\".")
oplist = ""
oplist += cmdname + " " 
def prgm(): 
    global oplist
    while 2 + 2 == 4:
        user = input(">")
        if user[0] == "-":
            if "*" in user:
                oplist += user[0:len(user) - 1] + " " 
                print("Now, enter the option's argument.")
                user = input(">")
                oplist += user[0:len(user) - 1] + " " 
                print("Option successfully added.")
                prgm()
            else: 
                oplist += user + " " 
                print("Option successfully added.")
                prgm()
        elif user == "q":
            print("Enter the command argument.")
            user = input(">")
            oplist += user
        else:
            print("Error. You didn't enter an option.")
            prgm()
        break
    print(oplist)
prgm()

输出输出的次数似乎取决于用户指定的选项数量，但我不知道为什么.另外，在IDLE中运行程序时，如果我在函数完成后手动打印(oplist)，则IDLE会像我希望的那样在一行上打印一次输出.为什么会这样呢?

The amount of times the output is printed seems to depend on how many options the user specifies, but I don't know why. In addition, when running the program in IDLE, if I manually print(oplist) after the function is finished, IDLE prints the output once on one line, like I intended it to. Why exactly is that the case?

推荐答案

将 print(oplist)移动到函数的末尾.由于您正在使用递归，因此该行被多次调用.

Move print(oplist) outside the function, to the last line of the program. Since you are using recursion, this line is called multiple times.

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