在C语言中，我的函数输出始终为0.000000.是因为两个输入都是int吗? [英] In C, my output of a function is always 0.000000. Is it because the two inputs are int?

问题描述

我知道您通常不打算发布所有代码，但这很简短，可以帮助解决问题.谁能解释输出为什么为0以及如何更改代码以输出应为圆锥体体积的东西.

I know you're usually not meant to put out all of your code but this is short and would help with the problem. Can anyone please explain why the output is 0 and how I can change the code to output what should be the volume of a cone.

#include <stdio.h>

float ConeVolume(int height, int radius);

float ConeVolume(int height, int radius)
{
    float pi;
    pi = 3.14159;
    float third;
    third = (1/3);
    float vol;
    vol = third * pi * radius * radius * height;
    return vol;
}


int main()
{
float x = ConeVolume(12,10);
printf("%.4f \n", x);
}

感谢所有回答如此迅速的人.这里的社区很棒.

edit: thank you to all who answered so quickly. Great community here.

推荐答案

1/3

是整数除法，总是结果为 0 .

is an integer division and always results in 0.

要对此求值为浮点变量，可以执行

To have this evaluate to a floating point variable you might do

1./3

或

1/3.

或

1./3.

或更明确的

(float)1/(float)3

例如.

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