如何截获脚本中的PHP函数调用? [英] How to intercept PHP function call in my script?

问题描述

我知道我可以使用 __ call 魔术方法拦截对象的方法调用.但是我该如何在脚本部分截获PHP函数(内置于PHP或由用户定义)呢?

I know that I can intercept method call with __call magic method for objects. But how I can intercept a PHP function (build in PHP or defined by user) call in my part of script?

例如，我有一些代码:

echo "Hello world";
$s = 0;
$i = $i + 5;
$str = str_repeat('Hi ', $i);
$hash = md5($str);
print $a;

我需要拦截 str_repeat()函数调用，并且不执行它及其后的所有代码并返回一些错误(或简单地执行 die('error'); )，这是真的吗?

I need to intercept str_repeat() function call and do not execute it and all code after it and return some error (or simply execute die('error');), is it real?

推荐答案

您是否检查了以下内容:

did you check this : http://www.java2s.com/Code/Php/Class/InterceptingMethodCallswiththecallMethodPHP5Only.htm ?

这并不复杂，但是您需要编写一些代码.

It's not complicated but you need to write a bit of code.

您还可以创建自己的拦截函数，该回调函数可以进行回调，而无需调用函数/方法，您可以通过自己的拦截函数传递它.

You can also create your own intercepting function that takes a callback and instead of calling your function/method you can pass it through your own intercepting function.

伪代码

function myFakeFunction(...){ ... }

function runFunction($functionName){
  // DO WHAT YOU WANT: INTERCEPTION
  call_user_func($functionName);
}
runFunction("myFakeFunction", ...);

在文档中

call_user_func .

注意:您应该关心两种方法的安全性问题.

NOTE: you should care about security issues for both methodologies.

我只是一个新主意，您还可以为要检查的所有方法创建一个共享对象，并在该对象上使用_call.但是我不确定那是否可以正常工作.

I just have a new idea, you can also create a shared object for all the methods that you want to check and use _call on that object. But I'm not sure if that would work correctly.

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