转换罗马/阿拉伯数字大于4000 [英] Converting roman/arabic numerals higher than 4000

问题描述

我要编写一个程序，将罗马数字转换为阿拉伯数字，反之亦然.我已经有一个可以转换4000以下数字的有效代码.对于大于或等于4000的罗马数字，写它们的新方法是括号表示乘以1000.例如4000是(IV)，6010是(VI)X等.感谢您的回答.丹尼尔

I am going to write a program that converts roman numerals to arabic and vice-versa. I already have a working code for converting numbers under 4000. For roman numerals higher than or equal to 4000 the new way to write them is that a parenthesis means multiplied by 1000. So for example 4000 is (IV), 6010 is (VI)X etc. Thankful for answer. Daniel

好的，以便解决此问题.罗马数字没有大于3999的数字，因此写更大数字的方法是在罗马数字周围加上一个小节(或括号)，这意味着数字应乘以1000

Ok so to clear up the problem. There is no roman numeral bigger than 3999, so a method to write bigger numbers is to put a bar (or a parenthesis) around a roman numeral meaning that numeral should be multiplied by 1000

当前功能:

def intToRoman(integer):
    rlist = romanList = [(1000, "M"),(900, "CM"),(500, "D"),(400, "CD"),(100, "C"),(90, "XC"),(50, "L"),(40, "XL"),(10, "X"),(9, "IX"),(5, "V"),(4, "IV"),(1, "I")]
    romanResult = ""
    for wholeNumber in rlist:
            while integer >= wholeNumber[0]:
                    integer -= wholeNumber[0]
                    romanResult += wholeNumber[1]
    return romanResult

def romanToInt(numeral):
    rlist = romanList = [(1000, "M"),(900, "CM"),(500, "D"),(400, "CD"),(100, "C"),(90, "XC"),(50, "L"),(40, "XL"),(10, "X"),(9, "IX"),(5, "V"),(4, "IV"),(1, "I")]
        index = 0
        intResult = 0
        for integer, romanNumeral in rlist:
            while numeral[index : index + len(romanNumeral)] == romanNumeral:
                intResult += integer
                index += len(romanNumeral)

推荐答案

您只需要两个函数.一种用于高于4000的数字，另一种用于低于4000的数字.

You simply need two functions. One for numbers higher than 4000 and one for numbers below.

def smallIntToRoman(integer):
    rlist = romanList = [(1000, "M"),(900, "CM"),(500, "D"),(400, "CD"),(100, "C"),(90, "XC"),(50, "L"),(40, "XL"),(10, "X"),(9, "IX"),(5, "V"),(4, "IV"),(1, "I")]
    romanResult = ""
    for wholeNumber in rlist:
            while integer >= wholeNumber[0]:
                    integer -= wholeNumber[0]
                    romanResult += wholeNumber[1]
    return romanResult

def bigIntToRoman(integer):
    thousands, rest = divmod(integer, 1000)
    return "({}){}".format(smallIntToRoman(thousands), smallIntToRoman(rest))

def intToRoman(integer):
    if integer >= 4000:
        return bigIntToRoman(integer)
    else:
        return smallIntToRoman(integer)


def smallRomanToInt(numeral):
    rlist = romanList = [(1000, "M"),(900, "CM"),(500, "D"),(400, "CD"),(100, "C"),(90, "XC"),(50, "L"),(40, "XL"),(10, "X"),(9, "IX"),(5, "V"),(4, "IV"),(1, "I")]
    if checkIfRomanNumeral(numeral) is False:
        pass
    elif checkIfRomanNumeral(numeral) is True:
        index = 0
        intResult = 0
        for integer, romanNumeral in rlist:
            while numeral[index : index + len(romanNumeral)] == romanNumeral:
                intResult += integer
                index += len(romanNumeral)

def romainToInt(numeral):
    if len(numeral) == 0:
        return None
    int_parts = numeral[1:].split(')') # Better done with regex
    if len(int_parts) == 1:
        return smallRomainToInt(numeral)
    elif len(int_parts) == 2:
        big = smallRomainToInt(int_parts[1])
        small = smallRomainToInt(int_parts[0])
        if big is None or small is None:
            return None
        else:
            return big * 1000 + small
    else:
        return None

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