数字的组合以达到给定的总和-R中的递归实现 [英] combinations of numbers to reach a given sum - recursive implementation in R
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问题描述
All I want to do is to implement the solution given here (the one in python) in R. I'm not very used to do debugging in R-Studio but even after I have tried that I still can't figure out why my code does not work. Basically (with the example input provided) I get the function to run over all the numbers and then it is stuck in a sort of infinite loop (or function). Can someone please point me in the right direction regarding this?
subset_sum <- function(numbers, target, partial = numeric(0)){
s <- sum(partial,na.rm = TRUE)
# check if the partial sum equals to target
if (s == target){
cat("sum(",partial,")","=",target)
}
else if (s >= target) {
return() # if we reach the number why bother to continue
}
else {
for(i in 1:length(numbers)){
n <- numbers[i]
remaining <- numbers[i+1:length(numbers)]
subset_sum(remaining, target, partial = append(partial,n))
}
}
}
subset_sum(c(3,9,8,4,5,7,10),15)
当不在调试模式下运行时,会出现以下错误:
When not run in debug mode it gives me these errors:
Error: node stack overflow
Error during wrapup: node stack overflow
推荐答案
这不是递归函数,但它利用了R处理矩阵/数组类型数据的能力.在#
This is not a recursive function but it takes advantage of R's ability to handle matrix/array type data. Some output is shown after #
v <- c(3,9,8,4,5,7,10)
v <- sort(v)
# [1] 3 4 5 7 8 9 10
target <- 15
# we don't need to check more than at most 4 numbers since 3+4+5+7 (the smallest numbers) is greater than 15
mincombs <- min(which(cumsum(v) > target))
# [1] 4
Combs <- combn(v, mincombs) # make combinations of numbers
ans <- mapply(function(x,y) ifelse(y > 0, paste0(paste0(Combs[1:y,x], collapse="+"), "=", target), NA), 1:ncol(Combs), apply(Combs, 2, function(I) which(cumsum(I) == target)))
ans <- unlist(ans[lengths(ans) > 0])
# [1] "3+4+8=15" "3+4+8=15" "3+5+7=15" "3+5+7=15" "3+5+7=15" "7+8=15"
在功能中
myfun <- function(V, target) {
V <- sort(V)
mincombs <- min(which(cumsum(V) > target))
Combs <- combn(V, mincombs)
ans <- mapply(function(x,y) ifelse(y > 0, paste0(paste0(Combs[1:y,x], collapse="+"), "=", target), NA), 1:ncol(Combs), apply(Combs, 2, function(I) which(cumsum(I) == target)))
ans <- unlist(ans[lengths(ans) > 0])
return(ans)
}
myfun(V = c(3,9,8,4,5,7,10), target = 15)
myfun(V = c(3,9,8,4,5,7,10,12,4,32),target = 20)
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