awk可以打印没有图案的行吗? [英] Can awk print lines that do not have a pattern?

问题描述

awk可以打印所有与其中一种模式不匹配的行吗?

Can awk print all lines that did not match one of the patterns?

换句话说，我想变换一些线条，但其余部分保持不变.因此，如果/pattern/匹配，我将提供一个自定义块来打印行.我只需要提供一个默认匹配器(如else)即可打印其他行.

In other words, I want to transform some lines but leave the rest unchanged. So, if a /pattern/ matched I would provide a custom block to print the line. I just need to provide a default matcher (like an else) to print the other lines.

推荐答案

是的，只需使用任何非零数字，awk就会执行其默认操作，即打印该行:

Yes, just use any non-zero number and awk will do its default thing which is to print the line:

awk '7' file

如果您希望将其作为"else"，请在为特殊处理选择的任何行之后加上"next"，这样就不会对它们执行同样的操作.

If you want it as an "else", put "next" after whatever lines you select for special processing so this one isn't executed for them too.

awk '/pattern/{special processing; next} 7' file

这篇关于awk可以打印没有图案的行吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！