sed搜索范围并打印第一组 [英] sed search a range and print first set

问题描述

我有一个如下文件

myname
_       something
_       something
_       something
myname
_       something
_       something
myname
_       something
and it follows and no standard other than myname word.

现在，我要打印从myname到找到myname的第一组搜索，如下所示.

Now I want to print the first set of search from myname to till myname found as below.

myname
_       something
_       something
_

我尝试使用以下内容，但不起作用.

I tried using the following but it is not working.

sed -n -e '/myname/,/myname/ p' file

它会打印所有设置.

对此也进行了尝试，但是没有用.

Tried this also but not worked.

sed -n '/myname/,$ p;/myname/q'

推荐答案

awk  '/myname/{if(b) exit; else b=1}1' filename



$ cat temp.txt
myname
_       something
_       something
_       something
myname
_       something
_       something
myname
_       something

$ awk  '/myname/{if(b) exit; else b=1}1' temp.txt
myname
_       something
_       something
_       something

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