TypeScript泛型类型的泛型类型 [英] TypeScript Generic type of a generic type

问题描述

是否可以传入需要另一种通用类型的通用类型?这是我想做的:

Is it possible to pass in a generic type that requires another generic type? Here's what I want to do:

abstract class MyClass<Stream> {
  abstract doSomething1(): Stream<number> // TS error here: Stream does not take generic parameter
  abstract doSomething2(): Stream<string> // TS error here: Stream does not take generic parameter
}

// Implementations of the abstract class:
class MyObservableClass extends MyClass<Observable> {
  doSomething1() { // returns Observable<number> }
  doSomething2() { // returns Observable<string> }
}

class MyPromiseClass extends MyClass<Promise> {
  doSomething1() { // returns Promise<number> }
  doSomething2() { // returns Promise<string> }
}

我也尝试过:

doSomething<Stream, T>(): Stream<T>

但也不起作用.

推荐答案

回答自己:目前还不可能(2019年1月).

Answering myself: it is not possible yet (Jan 2019).

此处正在讨论该问题: https://github.com/Microsoft/TypeScript/第1213个问题

The issue is being discussed here: https://github.com/Microsoft/TypeScript/issues/1213

这篇关于TypeScript泛型类型的泛型类型的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！