使用派生类类型作为基类的通用操作的参数 [英] Use derived class type as parameter of generic action of base class

问题描述

我想通过委托来操纵实例，这是类本身的属性.委托的参数应该始终是实例本身(即使在派生类中也是如此！).

I want to manipulate an instance by a delegate, which is a property of the class itself. The parameter of the delegate should always be the instance itself (even in derived classes!).

请参见下面的代码.我知道代码没有编译，因为我必须将car1转换为type，我正在寻找不进行转换的解决方案.

See code below. I know that the code is not compiling because I have to cast car1 to type car, I'm looking for a solution without casting.

代码

static void Main(string[] args)
{
    var car = new Car();
     car.VehicleManipulator = car1 => car1.SomeInt++;
     car.ManipulateVehicle();

    Console.WriteLine("end");
    Console.ReadLine();
}

internal class Vehicle
{
    public Action<Vehicle> VehicleManipulator { get; set; }

    public void ManipulateVehicle()
    {
        this.VehicleManipulator(this);
    }
}

internal class Car : Vehicle
{
    public int SomeInt { get; set; }
}

更改了密码！

我的问题是，有没有一个好的解决方案可以仅在基类中处理所有这些问题，但是在操作中我想使用派生类而不进行转换.

My question is, is there a good solution to handle all this just in the base class, but in the action I want to use the derived classes without casting.

推荐答案

如果要避免强制转换，请使Vehicle通用，如:

If you want to avoid casting, make Vehicle generic like:

class Vehicle<T> where T : Vehicle {
     Action<T> ManipulateVehicle { get; set; }
}

class Car : Vehicle<Car> {
    int SomeInt { get; set; }
}

看起来有点怪异，但是这意味着如果您有汽车实例，则操纵器可在汽车上工作，如果您有卡车，则其可在卡车上工作，依此类推.车辆可能应该是抽象的.

It looks a little weird but it means if you have an instance of car the manipulator works on cars and if you have a truck it works on trucks and so on. Vehicle should probably be abstract.

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