使用HTTP GET获取音频文件，然后在python 3中播放它.在python 3中运行TTS吗? [英] Get an audio file with HTTP GET and then play it in python 3. TTS in python 3?

问题描述

基本上我想要的是python 3中的TTS ...我已经尝试过pyttsx，但显然它仅适用于python 2我已经尝试过其他东西了...现在，我正在尝试使用 voicerss.org 中的api，但是我不知道如何通过HTTP获取它，然后再玩搭配pyglet的python ...

Basically what i want is TTS in python 3... I already tried pyttsx but aparently it only works with python 2 I already tried other things too... Now i'm trying with the api from voicerss.org but i can't figure out how can HTTP GET it and then play it with python with pyglet...

到目前为止，这是我的代码:

here is my code so far:

import pyglet
import urllib3

http = urllib3.PoolManager()
speechrequest = http.request('GET', 'http://api.voicerss.org/?key=04f49802d32d442ca997d4d2ea76d3d5&hl=pt-pt&c=wav&src=texto')
speech = pyglet.media.load(speechrequest)
speech.play()
pyglet.app.run()

错误是:

Traceback (most recent call last):
  File "C:/Users/Diogo/Documents/test.py", line 6, in <module>
    speech = pyglet.media.load(speechrequest)
  File "C:\Users\Diogo\AppData\Local\Programs\Python\Python35\lib\site-packages\pyglet\media\__init__.py", line 1429, in load
    source = get_source_loader().load(filename, file)
  File "C:\Users\Diogo\AppData\Local\Programs\Python\Python35\lib\site-packages\pyglet\media\__init__.py", line 1410, in load
    return riff.WaveSource(filename, file)
  File "C:\Users\Diogo\AppData\Local\Programs\Python\Python35\lib\site-packages\pyglet\media\riff.py", line 185, in __init__
    file = open(filename, 'rb')
TypeError: invalid file: <urllib3.response.HTTPResponse object at 0x0000002EB0730D30>

我想它没有将wav文件返回给python不知道为什么，因为.如果我输入' http://api.voicerss.org/?key=04f49802d32d442ca997d4d2ea76d3d5&hl=pt-pt&c=wav&src=texto '，它会返回一个wav文件...

i guess its not returning an wav file to python don't know why because. If i enter 'http://api.voicerss.org/?key=04f49802d32d442ca997d4d2ea76d3d5&hl=pt-pt&c=wav&src=texto' in internet explorer it returns a wav file...

所以，我的问题是:
我在代码中做错了什么，或者如果这样不可能，python怎么会说话?

So, my questions are:
what i am doing wrong with the code or if is impossible this way how can python speak?

请耐心等待，我只有18岁，而且我不会说英语，因为我是葡萄牙语...

Please be patient with me, i'm only 18 years old and i can't speak english properly, because i'm portuguese...

推荐答案

您可以在本地保存远程wav文件，并使用默认应用程序播放该文件:

You could save the remote wav file locally and play it using a default application:

#!/usr/bin/env python3
from urllib.request import urlretrieve
import webbrowser

filename = 'speech.wav'
urlretrieve("http://api.voicerss.org/?key=04f49802d32d442ca997d4d2ea76d3d5"
            "&hl=pt-pt&c=wav&src=texto", filename)
webbrowser.open(filename) # play the file using default application

在Windows上，您可以使用 os.startfile()代替 webbrowser.open()，或直接在Python中播放wav文件，而无需外部应用程序:/p>

On Windows, you could use os.startfile() instead of webbrowser.open() or to play the wav file directly in Python without an external application:

import winsound

winsound.PlaySound('speech.wav', winsound.SND_FILENAME)

---

您的代码至少有两个问题:

---

Your code have at least two issues:

1. 您应该将文件名(字符串)传递给 pyglet.media.load()函数，而不是 HTTPResponse 对象.
2. pyglet 可能仍然无法播放:我得到 pyglet.media.riff.RIFFFormatException:格式块的大小不正确.系统上的错误.

1. You should pass a filename (a string) to pyglet.media.load() function, not an HTTPResponse object.
2. pyglet may fail to play it anyway: I get pyglet.media.riff.RIFFFormatException: Size of format chunk is incorrect. error on my system.

---

您还可以播放远程wav文件而不将其保存到磁盘，即可以播放流式内容:

---

You could also play a remote wav file without saving it to disk i.e., you can play streaming content:

#!/usr/bin/env python3
from urllib.parse import quote
from urllib.request import urlopen

api_key = open('api.key', encoding='ascii').read().strip()
language = 'pt-pt'
text = quote("1 2 3")
playwav(urlopen('https://api.voicerss.org/?c=wav&f=8khz_8bit_mono&ssml=false&'
                'key={api_key}&src={text}&hl={language}'.format(**vars())))

其中 playwav():

import wave
from contextlib import closing

import pyaudio  # Windows: py -m pip install pyaudio
                # $ sudo apt-get install python{,3}-pyaudio
player = None
def playwav(path_or_file):
    global player
    if player is None:
        player = pyaudio.PyAudio()
    with closing(wave.open(path_or_file, 'rb')) as wavfile, \
         closing(player.open(
             format=player.get_format_from_width(wavfile.getsampwidth()),
             channels=wavfile.getnchannels(),
             rate=wavfile.getframerate(),
             output=True)) as stream:
        while True:
            data = wavfile.readframes(1024) # read 1024 frames at once
            if not data: # EOF
                break
            stream.write(data)

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