git stash drop最旧的存储(例如最旧的5个存储) [英] git stash drop oldest stashes ( say oldest 5 stashes)

问题描述

如何在一个语句中删除最旧的存储区(例如最旧的5个存储区)，而不是执行以下操作:

How do I drop oldest stashes (say oldest 5 stashes) in one statement instead of doing something like this:

git stash drop stash@{3}
git stash drop stash@{4}
git stash drop stash@{5}
git stash drop stash@{6}
git stash drop stash@{7}

推荐答案

感谢匿名用户的编辑，正确的命令应如下所示:

Thanks to an anonymous user's edit, the correct command would look like this:

git stash list | cut -f 1 -d : | tail -5 | sort -r | xargs -n 1 git stash drop

这是他/她的解释:

• git隐藏列表:列出所有隐藏列表
• cut -f 1 -d :仅选择第一列(存储标识符，例如stash @ {29})
• tail -5 :仅保留最后五行
• sort -r :反转行的顺序以首先删除最旧的存储区(否则，其余的存储区在每次删除后都会获得新名称)
• xargs -n 1 git stash drop :对于管道中传输的每一行，执行git stash drop，因为 git stash drop [可能]仅支持一个stash a.时间.

• git stash list: List all your stashes
• cut -f 1 -d: Select only the first column (stash identifier, for example stash@{29})
• tail -5: Keep only the last five lines
• sort -r: Invert the order of the lines to drop the oldest stash first (otherwise remaining stashes get new names after each removal)
• xargs -n 1 git stash drop: For each line transmitted in the pipe, execute git stash drop, since git stash drop [may] support only one stash a time.

所有对神秘陌生人的敬意.

All kudos to the mysterious stranger.

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