glibc检测到malloc():C中的内存损坏 [英] glibc detected malloc(): memory corruption in C
问题描述
我正在尝试在Linux下用C编写代码并得到此错误消息:
I am trying to compile and code written in C under linux, and got this error message:
glibc检测到malloc():内存损坏
glibc detected malloc(): memory corruption
我不知道为什么...
and I cannot find out why...
substring()只是通过提供起始索引和长度来返回原始字符串的一部分.例如substring("this is example",0,4)="this";
the substring() just return you part of the original string by giving the starting index and length. e.g. substring("this is example",0,4) = "this";
char *substring(char* str, int start, int length) {
char *newString = (char *)malloc(length * sizeof(char));
int i, x = 0;
int end=start+length-1;
for(i = start ; i <= end; i++){
newString[x++] = str[i];
}
newString[x] = '\0';
return newString;
}
和getCharIndexFirst()仅返回指定字符首次出现的索引getCharIndexLast()仅返回指定字符最后一次出现的索引
and the getCharIndexFirst() just returns the index of first occurance of the specified char the getCharIndexLast() just returns the index of last occurance of the specified char
及以下是主要功能:
//consoleCommand has the form of 'send MESSAGE ID', has the value from stdin
int firstSpace = getCharIndexFirst(consoleCommand,' ');
int lastSpace = getCharIndexLast(consoleCommand,' ');
int len = strlen(consoleCommand);
char *header = substring(consoleCommand,0,firstSpace);
printf("header is: %s\n",header);
char *cmd = substring(consoleCommand,firstSpace+1,lastSpace-firstSpace-1);
printf("command is: %s\n",cmd); // the code only runs up to here and output the error..
char *socketstr = substring(consoleCommand,lastSpace+1,len-lastSpace-1);
printf("socket is: %s\n",socketstr);
这里是更多信息:consoleCommand通常是标准输入,形式为发送消息ID",当消息长度为12个字符时会发生错误...例如发送此消息4",此消息"为cmd,长度为12个字符,这给了我错误!它适用于任何其他长度,我已经尝试过3、4、24 ...
感谢任何提示,谢谢!
推荐答案
newString[x] = '\0';
此时, x
等于 length
,这意味着您要在分配的内存末尾写入1个字符.您需要为另外一个字符分配空间.
At this point x
is equal to length
, which means you're writing 1 character beyond the end of the memory you allocated. You need to allocate space for one more character.
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