gnuplot:如何获取正确的星期数? [英] gnuplot: How to get correct week numbers?

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问题描述

从这个问题开始 gnuplot为什么警告:字符串中的时间格式错误,发现在某些情况下,使用时间指定符%W %U 的gnuplot中的星期数是错误的.

Originating from this question gnuplot why warning: Bad time format in string, there was the finding that the week numbers in gnuplot using the time specifiers %W and %U are wrong in some cases.

显然,周数的定义不同.此外,一周开始时有不同的定义,例如在星期日或星期一.经常使用的周数定义之一(不过,在美国和其他一些国家/地区不使用)是根据ISO 8601.

Apparently, there are different definitions of the week numbers. Furthermore, there are different definitions when a week starts, e.g. on Sunday or Monday. One definition for week numbers, which is commonly used (however, not in the US and a few other countries) is according to ISO 8601.

代码:(以说明错误的星期数)

Code: (to illustrate wrong week numbers)

### wrong week numbering in gnuplot with %W and %U
reset session

StartDate = "24.12.2020"
myTimeFmt = "%d.%m.%Y"
SecondsPerDay = 3600*24

print "      date   %a  %w  %d   %j  %W  %U"
print "===================================="
do for [i=0:20] {
    t = strptime(myTimeFmt,StartDate) + i*SecondsPerDay
    myDate = strftime(myTimeFmt."  %a  %w  %d  %j  %W  %U", t)
    print sprintf("%s", myDate)
}
### end of code

gnuplot时间说明符:

gnuplot time specifiers:

%a abbreviated name of day of the week
%w day of the week, 0–6 (Sunday = 0)
%d day of the month, 01–31
%j day of the year, 1–366 
%W week of the year (week starts on Monday)
%U week of the year (week starts on Sunday)

结果:

      date   %a  %w  %d   %j  %W  %U
====================================
24.12.2020  Thu  04  24  359  52  52
25.12.2020  Fri  05  25  360  52  52
26.12.2020  Sat  06  26  361  52  52
27.12.2020  Sun  00  27  362  52  53
28.12.2020  Mon  01  28  363  53  53
29.12.2020  Tue  02  29  364  53  53
30.12.2020  Wed  03  30  365  53  53
31.12.2020  Thu  04  31  366  53  53
01.01.2021  Fri  05  01  001  01  01   ???
02.01.2021  Sat  06  02  002  01  01   ???
03.01.2021  Sun  00  03  003  00  01   ???
04.01.2021  Mon  01  04  004  01  01
05.01.2021  Tue  02  05  005  01  01
06.01.2021  Wed  03  06  006  01  01
07.01.2021  Thu  04  07  007  01  01
08.01.2021  Fri  05  08  008  01  01
09.01.2021  Sat  06  09  009  01  01
10.01.2021  Sun  00  10  010  01  02
11.01.2021  Mon  01  11  011  02  02
12.01.2021  Tue  02  12  012  02  02
13.01.2021  Wed  03  13  013  02  02

问题:有解决此问题的解决方法吗?

Question: Is there a workaround to fix this?

推荐答案

基于此处的描述: https://en.wikipedia.org/wiki/ISO_week_date ,我猜想ISO 8601定义的实质是:

Based on the description here: https://en.wikipedia.org/wiki/ISO_week_date, I guess the essence of the ISO 8601 definition is:

  1. 一周从星期一开始
  2. 第01周是一年中第一个星期四的一周
  3. 一周属于大部分时间所在的年份
  4. 从星期四开始或结束的年有53周,其他有52周

代码:

### correct week number according to ISO 8601
reset session

dow(t)      = int(tm_wday(t)) ? tm_wday(t) : 7                               # day of week 1=Mon, ..., 7=Sun
week(t)     = int((11 + tm_yday(t) - dow(t))/7)                              # "raw"week of year
wday(d,m,y) = tm_wday(strptime("%d.%m.%Y",sprintf("%02d.%02d.%04d",d,m,y)))  # week day of certain date
wpy(y)      = wday(1,1,y)==4 || wday(31,12,y)==4 ? 53 : 52                   # weeks per year
woy(t)      = week(t) < 1 ? wpy(tm_year(t)-1) : \
              week(t) > wpy(tm_year(t)) ? 1 : week(t)                        # week of year
yow(t)      = int(week(t) < 1 ? tm_year(t)-1 : week(t) > wpy(tm_year(t)) ? \
              tm_year(t)+1 : tm_year(t))                                     # year of week (could be previous, current or next)

StartDate = "24.12.2020"
myTimeFmt = "%d.%m.%Y"
SecondsPerDay = 3600*24

print "      date   %a DoW  %d   %j   YoW WoY"
print "======================================"
do for [i=0:20] {
    t = strptime(myTimeFmt,StartDate) + i*SecondsPerDay
    myDate = strftime(myTimeFmt."  %a", t)
    myDate2 = strftime("%d  %j", t)
    print sprintf("%s  %02d  %s  %04d-W%02d", myDate, dow(t), myDate2, yow(t), woy(t))
}
### end of code

结果:

      date   %a DoW  %d   %j   YoW WoY
======================================
24.12.2020  Thu  04  24  359  2020-W52
25.12.2020  Fri  05  25  360  2020-W52
26.12.2020  Sat  06  26  361  2020-W52
27.12.2020  Sun  07  27  362  2020-W52
28.12.2020  Mon  01  28  363  2020-W53
29.12.2020  Tue  02  29  364  2020-W53
30.12.2020  Wed  03  30  365  2020-W53
31.12.2020  Thu  04  31  366  2020-W53
01.01.2021  Fri  05  01  001  2020-W53
02.01.2021  Sat  06  02  002  2020-W53
03.01.2021  Sun  07  03  003  2020-W53
04.01.2021  Mon  01  04  004  2021-W01
05.01.2021  Tue  02  05  005  2021-W01
06.01.2021  Wed  03  06  006  2021-W01
07.01.2021  Thu  04  07  007  2021-W01
08.01.2021  Fri  05  08  008  2021-W01
09.01.2021  Sat  06  09  009  2021-W01
10.01.2021  Sun  07  10  010  2021-W01
11.01.2021  Mon  01  11  011  2021-W02
12.01.2021  Tue  02  12  012  2021-W02
13.01.2021  Wed  03  13  013  2021-W02

为了使用星期数,例如作为时间轴标签,最好对%W 实施此操作.偶然地,SourceForge上最近有一个错误报告.因此,我认为它将在下一版本中很快得到修复.

In order to use the week numbers, e.g. as time axis labels it would be ideal to have this implemented for %W. Accidentially, there was a recent bug report on SourceForge. So, I assume it will be fixed pretty soon in one of the next versions.

这篇关于gnuplot:如何获取正确的星期数?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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