通过“运行"将CLI参数传递给可执行文件 [英] Passing CLI arguments to excutables with 'go run'
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问题描述
我有一个程序 readfile.go
,我想将命令行参数 os.Args [1]
也作为 readfile.go
.
I have a program readfile.go
and I want to give the command line argument os.Args[1]
also as readfile.go
.
但是,运行"认为它是自身的一个附加参数,而不是输出可执行文件.是否有一个标志可以告诉'go run'这是可执行文件的参数?
However 'go run' thinks that it is an additional argument to itself rather than to the output executable. Is there a flag which can tell 'go run' that this is an argument to executable?
mvaidya@mvaidya-VirtualBox:~/junkeork$ go run readfile.go readfile.go
package main: case-insensitive file name collision: "readfile.go" and "readfile.go"
mvaidya@mvaidya-VirtualBox:~/junkeork$
错误:
包主文件:不区分大小写的文件名冲突:"readfile.go"和" readfile.go"
package main: case-insensitive file name collision: "readfile.go" and "readfile.go"
推荐答案
您可以使用-
将gofiles与参数分开:
You can use --
to separate gofiles from arguments:
go run readfile.go -- readfile.go
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