如何用冒号解组XML属性? [英] How to unmarshal XML attributes with colons?

问题描述

我正在使用的某些SVG/XML文件的属性名称中带有破折号和冒号-例如:

Some SVG/XML files I'm working with have dashes and colons in attribute names - for example:

<g>
  <a xlink:href="http://example.com" data-bind="121">...</a>
</g>

我正在尝试使用 golang 的方法来解组这些属性 encoding/xml 包.虽然虚线属性有效，但带有冒号的属性不起作用:

I'm trying to figure out how to unmarshal these attributes using golang's encoding/xml package. While the dashed attributes works, the ones with the colon doesn't:

package main

import (
    "encoding/xml"
    "fmt"
)

var data = `
<g>
    <a xlink:href="http://example.com" data-bind="121">lala</a>
</g>
`

type Anchor struct {
    DataBind  int    `xml:"data-bind,attr"`  // this works
    XlinkHref string `xml:"xlink:href,attr"` // this fails
}

type Group struct {
    A Anchor `xml:"a"`
}

func main() {
    group := Group{}
    _ = xml.Unmarshal([]byte(data), &group)

    fmt.Printf("%#v\n", group.A)
}

这些是看似合法的属性名称；任何想法如何提取 xlink:href 一个?谢谢.

These are seemingly legal attribute names; any idea how to extract the xlink:href one? thanks.

推荐答案

您的示例片段不太正确，因为它不包含

Your example fragment is not quite correct, since it does not include an XML namespace binding for the xlink: prefix. What you probably want is:

<g xmlns:xlink="http://www.w3.org/1999/xlink">
  <a xlink:href="http://example.com" data-bind="121">lala</a>
</g>

您可以使用名称空间URL解封此属性:

You can unmarshal this attribute using the namespace URL:

XlinkHref string `xml:"http://www.w3.org/1999/xlink href,attr"`

此处是带有命名空间修复程序的示例程序的更新副本.

Here is an updated copy of your example program with the namespace fix.

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