Golang XML解析 [英] Golang XML parse

问题描述

我的XML数据:

 <词典版本="0.8"修订版="403605">< grammemes>< grammeme parent ="> POST</grammeme>< grammeme parent ="POST">名词</grammeme></grammemes></dictionary> 

我的代码:

  type字典struct {XMLName xml.Name`xml:"dictionary"`语法* Grammemes`xml:"grammemes"`}键入Grammemes struct {语法[] * Grammeme`xml:"grammeme"`}键入Grammeme struct {名称字符串`xml:"grammeme"`父字符串`xml:"parent，attr"`} 

我得到了Grammeme.Parent属性，但是我没有得到Grammeme.Name.为什么?

解决方案

如果希望字段包含当前元素的内容，则可以使用标记 xml:，chardata" .标记结构的方法是寻找< grammeme> 子元素.

因此，您可以解码的一组结构是:

  type字典struct {XMLName xml.Name`xml:"dictionary"`语法[] Grammeme`xml:"grammemes> grammeme"`}键入Grammeme struct {名称字符串`xml:，chardata"`父字符串`xml:"parent，attr"`} 

您可以在此处测试此示例: http://play.golang.org/p/7lQnQOCh0I

My XML data:

<dictionary version="0.8" revision="403605">
    <grammemes>
        <grammeme parent="">POST</grammeme>
        <grammeme parent="POST">NOUN</grammeme>
    </grammemes>
</dictionary>

My code:

type Dictionary struct {
    XMLName xml.Name `xml:"dictionary"`
    Grammemes *Grammemes `xml:"grammemes"`
}

type Grammemes struct {
    Grammemes []*Grammeme `xml:"grammeme"`
}

type Grammeme struct {
    Name string `xml:"grammeme"`
    Parent string `xml:"parent,attr"`
}

I get Grammeme.Parent attribute, but i don't get Grammeme.Name. Why?

解决方案

If you want a field to hold the contents of the current element, you can use the tag xml:",chardata". The way you've tagged your structure, it is instead looking for a <grammeme> sub-element.

So one set of structures you could decode into is:

type Dictionary struct {
    XMLName   xml.Name   `xml:"dictionary"`
    Grammemes []Grammeme `xml:"grammemes>grammeme"`
}

type Grammeme struct {
    Name   string `xml:",chardata"`
    Parent string `xml:"parent,attr"`
}

You can test out this example here: http://play.golang.org/p/7lQnQOCh0I

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