在golang中将字符串转换为数字 [英] string to number conversion in golang

问题描述

Golang具有 strconv 库，该库将字符串转换为int64和uint64.

Golang has strconv library that converts string to int64 and uint64.

但是，其余整数数据类型似乎不受支持，因为我找不到字节，int16，uint16，int32和uint32数据类型的转换函数.

However, the rest of integer data types seems to be unsupported as I can't find conversion functions for byte, int16, uint16, int32, uint32 data types.

始终可以从字节，16位和32位数据类型转换为int64和uint64，而不会损失精度.这是语言的意图吗?

One can always convert from byte, 16-bit and 32-bit data types to int64 and uint64 without loss of precision. Is that what's intended by language?

推荐答案

如果您更仔细地查看文档，则可以使用此方法；

If you look at the docs a bit more closely you can use this method;

func ParseInt(s string, base int, bitSize int)

https://golang.org/pkg/strconv/#ParseInt

bitSize 参数说明int的大小，因此您可以对 8 或 16 或 32 那些较小的整数类型. Atoi 在内部进行调用.我相信您想要 base 参数为 10 .像 b一样，err:= strconv.ParseInt("5"，10，8)表示一个字节.

The bitSize argument says how large the int is so you can do 8 or 16 or 32 for those smaller integer types. Atoi calls this internally. I believe you're wanting 10 for the base argument. So like b, err := strconv.ParseInt("5", 10, 8) for a byte.

如果OP实际上混淆了如何将16位int转换为字符串，则只需在此处添加一些答案即可...如果这是您的预期目标，请使用 fmt.Sprintf ，或者您可以执行从较小的int到较大的int的转换，因为它将始终成功.两者的例子； https://play.golang.org/p/UWSVxEmQ1N

Just going to add a couple things to the answer here in case the OP is in fact confused how to convert a 16-bit int into a string... If that is your intended goal just use fmt.Sprintf or you can do a conversion from smaller int to larger int as it will always succeed. Examples of both here; https://play.golang.org/p/UWSVxEmQ1N

package main

import "fmt"
import "strconv"

func main() {
    var a int16
    a = 5
    s := fmt.Sprintf("%d", a)
    s2 := strconv.Itoa(int(a))
    fmt.Println(s)
    fmt.Println(s2)
}

这篇关于在golang中将字符串转换为数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！