为什么这个curl命令不起作用? [英] Why is this curl command not working?

问题描述

您好，我只想创建一个简单的golang应用程序，它使用在identi.ca上发布一个新的凹痕.

Hi there I just want to create a simple golang applications, which posts a new dent at identi.ca using

curl -u username:password http://example.com/api/statuses/update.xml -d status='Howdy!' -d lat='30.468' -d long='-94.743'

到目前为止，这是我的代码，恕我直言，这应该起作用，但实际上它不起作用，有人知道如何解决此问题吗?

This is my code so far and imho this should work, but actually it isn't working, does anybody know how to fix this?

:不，我没有收到任何错误消息:/

Nope: I don't get any error messages :/

package main

import(
        "fmt"
        "os"
        "bufio"
        "exec"
)
func main() {

var err os.Error
var username string

print("Username: ")
_, err = fmt.Scanln(&username)
if err != nil {
    fmt.Println("Error: ", err)
}

var password string
print("Password: ")
_, err = fmt.Scanln(&password)
if err != nil {
    fmt.Println("Error: ", err)
}

var status string
print("Status: ")
in := bufio.NewReader(os.Stdin);
status, err = in.ReadString('\n');
if err != nil {
    fmt.Println("Error: ", err)
}

exec.Command("curl -u " + username + ":" + password + "https://identi.ca/api/statuses/update.xml -d status='" + status +  "'" + "-d source='API'").Run()

推荐答案

exec.Command()并不将整个命令行作为单个参数.您需要将其称为:

exec.Command() doesn't take the whole command line as a single argument. You need to call it as:

exec.Command("curl", "-u", username+":"+password, ...url..., "-d", "status="+status, "-d", "source=API").Run()

您怎么知道是否遇到错误?您无需检查 Run()的返回值.

How do you know if you get an error? You don't check the return value of Run().

您实际上应该将命令创建与运行分开.这样，您可以将进程的stdout和stderr设置为/dev/null 之外的其他值，例如

You should actually separate the command creation from running it. This way you can set the process's stdout and stderr to something besides /dev/null, e.g.

c := exec.Command("curl", "-u", username+":"+password, "https://identi.ca/api/statuses/update.xml", "-d", "status="+status, "-d", "source=API")
c.Stdout = os.Stdout
c.Stderr = os.Stderr
err = c.Run()
if err != nil {
    fmt.Println("Error: ", err)
}

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