C字符名称[8]到GoLang名称[8]字节 [英] C char name[8] to GoLang Name [8]byte

问题描述

我有一个C函数可以填充C结构:

I've got a C function that fills a C struct:

typedef struct {
  char name[8];
}

我需要将数据复制到具有相同内容的Go lang结构中:

I need to copy data into Go lang struct that has the same content:

type sData struct {
  Name [8]byte
}

该结构具有多个尺寸的参数:4、12、32，因此最好具有一个功能不只一个尺寸的函数.

The structure has parameters of multiple sizes: 4, 12, 32 so it would be nice to have a function that deals with more than just one size.

谢谢

推荐答案

要使其通用一些，可以将C char数组分解为 * C.char ，然后使用 unsafe.Pointer 将其投射回数组.

To make this a little more generic, you can decompose the C char array to a *C.char, then use unsafe.Pointer to cast it back to an array.

func charToBytes(dest []byte, src *C.char) {
    n := len(dest)
    copy(dest, (*(*[1024]byte)(unsafe.Pointer(src)))[:n:n])
}

也许更简单

func charToBytes(src *C.char, sz int) []byte {
    dest := make([]byte, sz)
    copy(dest, (*(*[1024]byte)(unsafe.Pointer(src)))[:sz:sz])
    return dest
}

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