为什么golang没有封送json对象? [英] Why golang didn't marshal the json object?

问题描述

我想知道为什么以下内容无法成功编组json吗?我正在尝试使用一个非常简单的示例来学习json包.

I wonder why the following didn't marshall to json successfully? I am trying to use a very simple example to learn json package.

package main

import (
    "encoding/json"
    "fmt"
)

type Message struct {
    username string `json:"name"`
    message  string `json:"message"`
}

func main() {
    var m = Message{
        username: "hello",
        message:  "world",
    }

    js, _ := json.Marshal(m)

    fmt.Println(m)
    fmt.Println(string(js))
}

推荐答案

username
message

以小写字母开头，表示它们未导出(认为是私有的)，因此对于 encoding/json 包不可见.您需要导出字段，或实现 MarshalJSON()([] byte，error)方法并自己完成.

start with a lowercase letter, meaning they are unexported (think private), and so are not visible to the encoding/json package. You need to export your fields, or implement the MarshalJSON() ([]byte, error) method and do it yourself.

这篇关于为什么golang没有封送json对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！