Google Apps脚本:如何将Google表格(仅一个)保存为云端硬盘文件夹为PDF? [英] Google Apps Script: How to save (Just one) Google Sheet to Drive Folder as PDF?
问题描述
仅将打开的名为"POTemplate"的Google表格以PDF本身的格式保存到Google云端硬盘上名为"Eric"的文件夹中.在第二到最后一行被卡住,这会导致错误,指出找不到文件夹Iterator.
Working to save just my open Google Sheet named 'POTemplate' as a PDF version of itself to a folder named 'Eric' on my Google Drive. Getting snagged on the 2nd to last line that brings an error stating the folder Iterator cannot be found.
function checkSheet() {
var sheetName = "POTemplate";
var folder = "Eric";
var pdfName = "Sample PO "
var sourceSpreadsheet = SpreadsheetApp.getActive();
var sourceSheet = sourceSpreadsheet.getSheetByName(sheetName);
var folder = DriveApp.getFoldersByName(folder);
var destSpreadsheet = SpreadsheetApp.open(DriveApp.getFileById(sourceSpreadsheet.getId()).makeCopy(folder));
var sheets = destSpreadsheet.getSheets();
for (i = 0; i < sheets.length; i++) {
if (sheets[i].getSheetName() != sheetName){
destSpreadsheet.deleteSheet(sheets[i])}};
var destSheet = destSpreadsheet.getSheets()[0];
var sourceRange = sourceSheet.getRange(1,1,sourceSheet.getMaxRows(),sourceSheet.getMaxColumns());
var sourcevalues = sourceRange.getValues();
var destRange = destSheet.getRange(1, 1, destSheet.getMaxRows(),
destSheet.getMaxColumns());
destRange.setValues(sourcevalues);
var theBlob = destSpreadsheet.getBlob().getAs('application/pdf').setName(pdfName);
var newFile = folder.createFile(theBlob);
DriveApp.getFileById(destSpreadsheet.getId()).setTrashed(true);
}
推荐答案
以下函数返回返回名为 folder
var folder = DriveApp.getFoldersByName(folder);
要在FolderIterator的第一个文件夹中创建文件,则必须像下面这样专门定义它:
To create a file in the first folder in the FolderIterator, you will have to define it specifically like so:
var newFile = folder.next().createFile(theBlob);
您还可以检查folderIterator是否有任何文件夹,像这样:
You can also check if the folderIterator has any folders, to begin with, like so:
if(folder.hasNext()){
var newFile = folder.next().createFile(theBlob);
} else {
DriveApp.createFolder("Eric").createFile(theBlob)
}
代码改进:(可选)以下几行代码似乎没有任何目的
Code Improvements:(Optional) The following lines code, doesn't seem to have any purpose
var destSheet = destSpreadsheet.getSheets()[0];
var sourceRange = sourceSheet.getRange(1,1,sourceSheet.getMaxRows(),sourceSheet.getMaxColumns());
var sourcevalues = sourceRange.getValues();
var destRange = destSheet.getRange(1, 1, destSheet.getMaxRows(),
destSheet.getMaxColumns());
destRange.setValues(sourcevalues);
由于您要复制原始电子表格,因此工作表"POTemplate"将完全相同.因此,似乎没有必要再次复制它.
Since you are making a copy of your original spreadsheet, your sheet "POTemplate" will be exactly the same. So, there seems to be no point copying it again.
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