从字幕文件中删除不在单词列表中的(常用单词)单词 [英] Remove words from a subtitle file that aren't in a wordlist (of common words)
问题描述
我有一些字幕文件,并且我不想学习这些字幕中的每个单词,因此无需学习一些较难的术语,例如:颅骨,发育不良...
I have some subtitle files, and I'm not intending to learn every single word in these subtitles, there is no need to learn some hard terms like: cleidocranial, dysplasia...
我在这里找到此脚本:从中删除单词不在列表中的单元格.但是我不知道如何修改或运行它.(我正在使用linux)
I found this script here: Remove words from a cell that aren't in a list. But I have no idea how to modify it or run it. (I'm using linux)
这是我们的示例:
字幕文件(.srt):
2
00:00:13,000->00:00:15,000
颅骨发育不良的人很好.
2
00:00:13,000 --> 00:00:15,000
People with cleidocranial dysplasia are good.
3000个常用单词(.txt)的单词列表:
...
人
与
是
好
...
...
people
with
are
good
...
我们需要的输出(.srt):
2
00:00:13,000->00:00:15,000
有* *的人很好.
2
00:00:13,000 --> 00:00:15,000
People with * * are good.
或仅在可能的情况下将其标记为(.srt):
2
00:00:13,000->00:00:15,000
颅骨*不典型增生*的人很好.
2
00:00:13,000 --> 00:00:15,000
People with cleidocranial* dysplasia* are good.
如果有一种仅适用于纯文本(没有时间码)的解决方案,没关系,只需说明如何运行
谢谢.
If there is a solution working just with plain texts (without timecodes), it's ok, just explain how to run it
Thank you.
推荐答案
以下仅处理每个'.srt'
文件的第三行.它可以轻松地用于处理其他行和/或其他文件.
The following processes the 3rd line only of every '.srt'
file. It can be easily adapted to process other lines and/or other files.
import os
import re
from glob import glob
with open('words.txt') as f:
keep_words = {line.strip().lower() for line in f}
for filename_in in glob('*.srt'):
filename_out = f'{os.path.splitext(filename_in)[0]}_new.srt'
with open(filename_in) as fin, open(filename_out, 'w') as fout:
for i, line in enumerate(fin):
if i == 2:
parts = re.split(r"([\w']+)", line.strip())
parts[1::2] = [w if w.lower() in keep_words else '*' for w in parts[1::2]]
line = ''.join(parts) + '\n'
fout.write(line)
结果(对于您作为示例给出的 subtitle.rst
:
Result (for the subtitle.rst
you gave as example:
! cat subtitle_new.rst
2
00:00:13,000 --> 00:00:15,000
People with * * are good.
替代方法:只需在词汇以外的单词旁边添加'*'
:
Alternative: just add a '*'
next to out-of-vocabulary words:
# replace:
# parts[1::2] = [w if w.lower() in keep_words else '*' for w in parts[1::2]]
parts[1::2] = [w if w.lower() in keep_words else f'{w}*' for w in parts[1::2]]
则输出为:
2
00:00:13,000 --> 00:00:15,000
People with cleidocranial* dysplasia* are good.
说明:
- 第一个
open
用于读取所有想要的单词,确保它们都是小写,然后将它们放入set
中(用于快速成员资格测试)./li> - 我们使用
glob
查找以'.srt'
结尾的所有文件名. - 对于每个这样的文件,我们都构造一个新文件名,作为
'..._ new.srt'
. - 我们阅读了所有行,但仅修改了
i == 2
行(即第三行,因为默认情况下enumerate
从0开始). -
line.strip()
删除尾随的换行符. - 我们本可以使用
line.strip().split()
将行拆分为单词,但是最后将'good.'
保留为最后一个单词;不好.使用的正则表达式通常用于拆分单词(特别是,它用单引号引起来,例如"do n't"
;它可能不是您想要的,当然可以随意使用) - 我们使用捕获组拆分
r(([\ w'] +)"
,而不是拆分非单词char,这样我们既拥有单词又将它们分隔在零件
.例如,好人".
成为[",人",,",谁",,",,",好"','.']
. - 单词本身是
parts
的所有其他元素,从索引1开始. - 如果单词的小写形式不是
keep_words
,我们会用'*'
替换这些单词. - 最后,我们重新组装该行,并通常将所有行输出到新文件中.
- The first
open
is used to read in all wanted words, make sure they are in lowercase, and put them into aset
(for fast membership test). - We use
glob
to find all filenames ending in'.srt'
. - For each such file, we construct a new filename derived from it as
'..._new.srt'
. - We read in all lines, but modify only line
i == 2
(i.e. the 3rd line, sinceenumerate
by default starts at 0). line.strip()
removes the trailing newline.- We could have used
line.strip().split()
to split the line into words, but it would have left'good.'
as the last word; not good. The regex used is often used to split words (in particular, it leaves in single quotes such as"don't"
; it may or may not be what you want, adapt at will of course). - We use a capturing group split
r"([\w']+)"
instead of splitting on non-word chars, so that we have both words and what separates them inparts
. For example,'People, who are good.'
becomes['', 'People', ', ', 'who', ' ', 'are', ' ', 'good', '.']
. - The words themselves are every other element of
parts
, starting at index 1. - We replace the words by
'*'
if their lowercase form is not inkeep_words
. - Finally we re-assemble that line, and generally output all lines to the new file.
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