为什么java.lang.VerifyError是什么意思? [英] Why does java.lang.VerifyError mean?

问题描述

尽管我尝试将以下代码段与Groovy 运算符结合使用，以说明发生了 VerifyError .你们有什么想法吗?

While I've tried to use the following code snippet with the Groovy in-operator explanation the VerifyError has occured. Have you guys any idea about?

代码和控制台输出如下.

The code and console output is below.

class Hello extends ArrayList {
    boolean isCase(Object val) {
        return val == 66
    }

    static void main(args) {
        def myList = new Hello()
        myList << 55
        assert 66 in myList
        assert !myList.contains(66)
    }
}

错误日志:

Exception in thread "main" java.lang.VerifyError: (class: Hello, method: super$1$stream signature: ()Ljava/util/stream/Stream;) Illegal use of nonvirtual function call
    at java.lang.Class.forName0(Native Method)
    at java.lang.Class.forName(Class.java:259)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:116)

代码源自主题 Groovy如何在接线员工作?.

更新:

Groovy版本:1.8.6 JVM:1.6.0_45供应商:Sun Microsystems Inc.操作系统:Linux

Groovy Version: 1.8.6 JVM: 1.6.0_45 Vendor: Sun Microsystems Inc. OS: Linux

推荐答案

检查一下.它用于Java，但通常存在的问题是您使用的库版本错误.该类在那里，但是版本与预期不同.

Check this out. It's for Java, but generally problem is, that you are using wrong library versions. The class is there, but different version than expected.

http://craftingjava.blogspot.co.uk/2012/08/3-reasons-for-javalangverfiyerror.html

可能您搞砸了Groovy或Java SDK的安装.

Probably you have messed up Groovy or Java SDK installations.

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