groovy"...".execute()在Windows上有效，但在Linux上失败 [英] groovy "...".execute() works on windows but fails on linux

问题描述

此行在我的linux框上的Windows上正常运行时，它返回退出代码1.

while this line works fine on windows on my linux box it returns exit code 1.

"gnuplot -e \"set output '${imageFile.toString()}'; filename='${dataFile.toString()}'; ${args}\" \"${plotFile.toString()}\"".execute()

但是，如果我仅在终端上执行此操作，则一切正常.

But if I execute just this from the terminal everything works.

gnuplot -e "set output '/tmp/hrp-current.jpg'; filename='/tmp/a731265b-3736-4bb9-acf4-b92c1a09b999.csv'; " "/tmp/hrp/build/groovy/../gnuplot/hrp-current.gnuplot"

我在这里想念什么?某种程度上，它与gnuplot写入文件有关，因为在退出代码为1的linux上，"some_command> some.file"也会失败，而在Windows上可以正常工作.

What am I missing here? It somehow has to do with the fact that gnuplot writes to a file because `some_command > some.file" also fails on linux with exit code 1 while it would work fine on windows.

推荐答案

实际上是一些文件写入问题，因此我需要gnuplot将其输出通过管道传输到stdout，然后从groovy脚本中读取它并在其中读取输出流，然后保存到文件中:

Indeed it is some file writing issue so I need gnuplot to pipe its outout to stdout and then consume it from my groovy script where I read the outputstream and then save it to a file:

def out = new ByteArrayOutputStream()
def err = new ByteArrayOutputStream()
process.waitForProcessOutput(out, err)

这篇关于groovy"...".execute()在Windows上有效，但在Linux上失败的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！