pandas 通过多个字段分组然后比较 [英] Pandas groupby multiple fields then diff
问题描述
所以我的数据框看起来像这样:
So my dataframe looks like this:
from pandas.compat import StringIO
d = StringIO('''
date,site,country,score
2018-01-01,google,us,100
2018-01-01,google,ch,50
2018-01-02,google,us,70
2018-01-03,google,us,60
2018-01-02,google,ch,10
2018-01-01,fb,us,50
2018-01-02,fb,us,55
2018-01-03,fb,us,100
2018-01-01,fb,es,100
2018-01-02,fb,gb,100
''')
df = pd.read_csv(d, sep=",")
每个站点
的得分不同,具体取决于国家/地区
.我正在尝试查找每种 site
/ country
组合的得分
的1/3/5天的差异.
Each site
has a different score depending on the country
. I'm trying to find the 1/3/5-day difference of score
s for each site
/country
combination.
输出应为:
date,site,country,score,1_day_diff
2018-01-01,google,ch,50,0
2018-01-02,google,ch,10,-40
2018-01-01,google,us,100,0
2018-01-02,google,us,70,-30
2018-01-03,google,us,60,-10
2018-01-01,fb,es,100,0
2018-01-02,fb,gb,100,0
2018-01-01,fb,us,50,0
2018-01-02,fb,us,55,5
2018-01-03,fb,us,100,45
我首先尝试按 site
/ country
/ date
进行排序,然后按 site
和进行分组国家/地区
,但我无法从分组对象中脱颖而出.
I first tried sorting by site
/country
/date
, then grouping by site
and country
but I'm not able to wrap my head around getting a difference from a grouped object.
推荐答案
首先,对DataFrame进行排序,然后只需要 groupby.diff()
:
First, sort the DataFrame and then all you need is groupby.diff()
:
df = df.sort_values(by=['site', 'country', 'date'])
df['diff'] = df.groupby(['site', 'country'])['score'].diff().fillna(0)
df
Out:
date site country score diff
8 2018-01-01 fb es 100 0.0
9 2018-01-02 fb gb 100 0.0
5 2018-01-01 fb us 50 0.0
6 2018-01-02 fb us 55 5.0
7 2018-01-03 fb us 100 45.0
1 2018-01-01 google ch 50 0.0
4 2018-01-02 google ch 10 -40.0
0 2018-01-01 google us 100 0.0
2 2018-01-02 google us 70 -30.0
3 2018-01-03 google us 60 -10.0
sort_values
不支持任意排序.如果您需要任意排序(例如Google在fb之前),则需要将它们存储在集合中,并将列设置为分类.然后sort_values将遵守您在此处提供的顺序.
sort_values
doesn't support arbitrary orderings. If you need to sort arbitrarily (google before fb for example) you need to store them in a collection and set your column as categorical. Then sort_values will respect the ordering you provided there.
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