SQL MIN()和通过...分组 [英] SQL MIN() & GROUP BY
问题描述
我正在寻找一种更优雅的解决方案,以解决MySQL MIN()与GROUP BY结合使用的问题.
I'm searching for a more elegant solution to a problem I'm having with MySQL MIN() used in conjunction with GROUP BY.
我有两个表:
- 产品(id,group_id)
- product_attributes(product_id,attribute_id,值)
我希望从某个产品组的每个金属组(attribute_id = 40)中选择最便宜的金属.
I wish to select the cheapest metal out of each metal group (attribute_id = 40) from a certain product group.
以下查询有效,但我可以肯定它可以写得更好.
The following query works but I'm quite certain it could have been written much better.
SELECT metal.product_id, metal.value AS `metal`, `price`.value AS `price`
FROM
product_attributes metal
INNER JOIN
(
SELECT metal.value AS `metal`, MIN(price.value) AS `price`
FROM
product_attributes metal
LEFT JOIN
product_attributes price
ON metal.product_id = price.product_id
INNER JOIN products p
ON p.id = metal.product_id
WHERE
metal.attribute_id = 40 AND
price.attribute_id = 37 AND
p.group_id = 1
GROUP BY
metal.value
ORDER BY metal ASC, price DESC
) AS d ON
d.metal = metal.value
LEFT JOIN
product_attributes price ON
metal.product_id = price.product_id AND price.attribute_id = 37
INNER JOIN
products p ON
p.id = metal.product_id
WHERE
metal.attribute_id = 40
AND d.price = price.value
AND p.group_id = 1
GROUP BY
metal.value
ORDER BY
metal.value ASC,
price.value DESC;
推荐答案
解决方案最终比我要简单.我已经在内部查询中按价格对数据进行了排序,因此在GROUP BY之前强制进行排序,这样我就可以准确地获得所需的东西(每个金属组中最便宜的产品).
The solution finally was simpler than I though. I've ordered my data by price in an inner query, thus forcing a sort before GROUP BY, this way I get exactly what I need (the cheapest product from each metal group).
SELECT * FROM
(
SELECT metal.enum_id AS `metal`, metal.product_id FROM product_attributes metal
LEFT JOIN product_attributes price ON metal.product_id = price.product_id AND price.attribute_id = 37
INNER JOIN products p ON p.id = metal.product_id
WHERE
metal.attribute_id = 40 AND
p.group_id = 1 AND
p.id NOT IN (SELECT DISTINCT product_id FROM product_attributes WHERE (attribute_id=162 OR attribute_id=204 OR attribute_id=205) AND `value`=1)
ORDER BY price.value+'0' ASC
) AS s
GROUP BY metal
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