在Flask App中模拟gRPC状态代码("RpcError"对象没有属性"code") [英] Mocking gRPC status code ('RpcError' object has no attribute 'code') in Flask App
问题描述
我必须创建一个可以模拟特定grpc状态代码的单元测试(在我的情况下,我需要NOT_FOUND状态).
I have to create a unittest that should mock a specific grpc status code (in my case I need NOT_FOUND status).
这是我要嘲笑的东西:
try:
# my mocked function
except grpc.RpcError as e:
if e.code() == grpc.StatusCode.NOT_FOUND:
# do something
到目前为止,我的单元测试是这样的:
My unittest until now looks like this:
def mock_function_which_raise_RpcError():
e = grpc.RpcError(grpc.StatusCode.NOT_FOUND)
raise e
class MyTestCase(BaseViewTestCase):
@property
def base_url(self):
return '/myurl'
@mock.patch('my_func', mock_function_which_raise_RpcError)
def test_service_config_with_grpc_status_error(self):
# some code
assert resp.status_code == 404
首先,当我运行我的flask应用程序并请求具有特定正文的URL时,应该引发RpcError,一切正常.可以识别 e.code()
.另一方面,当我想运行该单元测试时,我得到 AttributeError:'RpcError'对象没有属性'code'
.
First thing first, when I run my flask app and make a request to a URL with a specific body which should raise that RpcError, everything works just fine. e.code()
is recognized. On the other hand, when i want to run that unittest, I get AttributeError: 'RpcError' object has no attribute 'code'
.
有什么想法吗?
推荐答案
似乎无法像在 grpc
RpcError 对象>代码(用C编写).但是,您可以使用以下方法来模拟行为:
Looks like you cannot construct a valid RpcError
object from Python the same way it is created in the grpc
code (which is written in C). You can, however, emulate the behavior by using:
def mock_function_which_raise_RpcError():
e = grpc.RpcError()
e.code = lambda: grpc.StatusCode.NOT_FOUND
raise e
或者,您可以派生自己的异常:
Alternatively, you can derive your own exception:
class MyRpcError(grpc.RpcError):
def __init__(self, code):
self._code = code
def code(self):
return self._code
def mock_function_which_raise_RpcError():
raise MyRpcError(grpc.StatusCode.NOT_FOUND)
更新:
添加了丢失的 code
方法,如MartinGrůber在评论中所述.
Update:
Added missing code
method as mentioned by Martin Grůber in the comments.
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