Haskell从字符串获取字符数组? [英] Haskell get character array from string?

问题描述

是否可以给定一个字符串，让我获得组成该字符串的每个字符?

Is it possible if given a string I could get each character composing that string?

推荐答案

在Haskell中，字符串只是(喜欢的)字符列表.你可以找到线

In Haskell, strings are just (liked) lists of characters; you can find the line

type String = [Char]

每个Haskell实现的源代码中的某个位置.这使得诸如查找某个特定字符的首次出现( elemIndex'a'mystring )或计算每个字符的出现频率( map(head&& length))等任务成为可能.组.排序)无关紧要.

somewhere in the source of every Haskell implementation. That makes tasks such as finding the first occurence of a certain character (elemIndex 'a' mystring) or calculating the frequency of each character (map (head &&& length) . group . sort) trivial.

因此，您也可以对带有字符串的列表使用常规语法.实际上，"foo" 只是 ['f'，'o'，'o'] 的糖，而这反过来又是'f'的糖:'o':'o':[] .您可以根据需要在它们上进行图案匹配，映射和折叠.例如，如果要使元素位于 mystring 的 n 位置，则可以使用 mystring！n ，前提是 0< = n<长度为mystring .

Because of this, you can use the usual syntax for lists with strings, too. Actually, "foo" is just sugar for ['f','o','o'], which in turn is just sugar for 'f' : 'o' : 'o' : []. You can pattern match, map and fold on them as you like. For instance, if you want to get the element at position n of mystring, you could use mystring !! n, provided that 0 <= n < length mystring.

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