当字段渴望时出现LazyInitializationException [英] LazyInitializationException when field is eager

问题描述

我有这样的课程 OmQcActivity :

@Entity
@Cache(usage = CacheConcurrencyStrategy.READ_WRITE)
@Table(name="OM_QC_ACTIVITY")
public class OmQcActivity{
   @ManyToOne(fetch = FetchType.EAGER)
   @JoinColumn(name="STATUS_ID")
   private Codesc status;
}

codesc是另一个实体.

codesc is another entity.

在我的代码中，我写道:

In my code I wrote:

OmQcActivity  myactivity = findQCActivityById(5);
Codesc status = myactivity.getCodesc();

@Transactional(readOnly = true, propagation = Propagation.SUPPORTS)
    public OmQcActivity findQCActivityById(Long id) {
        return session.load(persistentClass, id);
    }

但是，我得到了:

org.hibernate.LazyInitializationException: could not initialize proxy - no Session
    at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:86)
    at org.hibernate.proxy.AbstractLazyInitializer.getImplementation(AbstractLazyInitializer.java:140)
    at org.hibernate.proxy.pojo.javassist.JavassistLazyInitializer.invoke(JavassistLazyInitializer.java:190)
    at com.mycompany.model.OmQcActivity_$$_javassist_11.getStatus(OmQcActivity_$$_javassist_11.java)

如果获取类型渴望，如何获得Lazy异常?

how can I get Lazy exception if the fetch type is eager?

推荐答案

load()不会立即加载实体，它返回一个惰性代理，该代理在第一个方法调用时获取实际数据.在大多数情况下，您需要使用 get()而不是 load().

load() doesn't load an entity immediately, it returns a lazy proxy that fetches the real data at the first method call. In most cases you need to use get() instead of load().

这篇关于当字段渴望时出现LazyInitializationException的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！